CBLOCK 0x000 ;              i, j, k ;              ENDC              ORG    0              goto main           org 0x0200      main                movlw  0x00                incf   i,f                  addwfc i+1,f                  movff  i,k                   movf   k,w                subwf  j,f                movf   k+1,w                subwfb j+1,f here           goto here

Q: adres veri 01h 5x9 02h 5x8 190100 7155 08h 871580 5x2 09h 5x1 Write the asm code that will create…

A: F000 21, 50 F0   LXI H,F050H memory location where number is stored F003 46   MOV B,M the number…

Q: ORG 100h CLD LEA SI, a1 LEA DI, a2 MOV CX, 3 REP MOVSB RET a1 DB 1,15,9 a2 DB 3 DUP(0)…

A: According to the information given:- We have to run the mentioned code and find out the content of…

Q: Large address space 2n where n = word length May be nested, multilevel, cascaded - e.g. EA = (((A)))…

A: Introduction

Q: he contents of the following registers are: CS = 2212 H DS = 4040 H SS = 3025 H IP = 2230 H SP =…

A: We are going to find out physical addresses of CS,DS, and SS. I have uploaded image for the solution…

Q: a. Find the number of bits for the main memory address. ANSWER: b. How many blocks are there in a…

A: Here in this question we have given Main memory capacity= 4GB Block size = 32 B  Cache size = 64 kB.…

Q: For a 512k x 32 memory system, how many unique address locations are there? Give the exact number. O…

A: Given, Size of memory system = 512k x 32 For a q x r memory system, Number of unique address…

Q: A cache is set up with a block size of 32 words. There are 16 blocks in cache and set up to be…

A: Block size = 32 words  Block Offset = 5 bits Total # of blocks inside cache = 16 So index bits = 4…

Q: QI Answer with "True" or "False" Interrupt is automatic procedure call initiated by some exceptional…

A: Note: As per Q and A guidelines, we are supposed to answer only 4 subparts, hence answering from (a)…

Q: In a page addressing system of 15 bits, where eight bits are used for the page number, what would be…

A: The above question is solved in step 2 :-

Q: 17- The (CS:IP) of the ISR of NMI are stored in the IVT, starting at address: a. 00000H b. 00002H c.…

A: 17- The (CS:IP) of the ISR of NMI are stored in the IVT, starting at address: a. 00000H b. 00002H c.…

Q: BR main .BLOCK 2 х: 2 .BLOCK y: temp: main: .EQUATE O 3,i х,d 8,i y,d 2,i temp,s x,d y,d temp,s х,d…

A: Given code segment BR main                      // branch to main loop x:    .BLOCK 2…

Q: = E=

A: Given, Physical address 32 bits 32KB L1 Data Cache, 64B line size/Block size  and 2 way set…

Q: Upon execution of MOV [BP+01], SI with DS = 2000, SS = 4000 H, BP = 3000 H, SI = %3D 4588 , the…

A: We need to consider the 20-bit address, so when we multiply with 220 the answer is 24589.

Q: A cache is set up with a block size of 8 words. There are 128 words in cache and set up to be direct…

A: First find number of blocks = total blocks in cache/ block size. = 128/8 = 16 Assuming each word is…

Q: A computer has four page frames. The time of loading, time of last access and the R and M bits for…

A: The Answer is in Below Steps

Q: calculate P(e | w1) Calculate P(e|wl) Cache warning W W memory-size Warning W Over flow Error Stack…

A: P(e/w1) = P(e and w1) / P(w1) P(e/w1) = P(e)P(w1) / P(w1) P(e/w1) = P(e)  Explanation: Assuming…

Q: Label Microoperations CD BR AD ORG O ADD: NOP READ I CALL INDRCT NEXT JMP JMP U ADD U FETCH ORG 4…

A: If I=0, the operand is read in the first microinstruction and added to AC in the second.

Q: Grouping the Os in the K-map shown below will give us groups. CD 00 01 11 10 AB 00 0000 01 0|1 1 | 1…

A: As given, we need to group the 0s in the given K-map. The given K-map is -

Q: ? An abbreviation for "memory address" is a mnemonic address. How many distinct domains are feasible…

A: IP address: An Internet Protocol address (IP address) is a mathematical mark, for example, 192.0.2.1…

Q: What are the physical addresses for the following logical address your work A) 3 B) 9 C) 14 Consider…

A: Page size is 4 Bytes. So page offset is 2 bits.  1. Logical address = 3 = 00011 Page offset is 11…

Q: Virtual Page numbers 0x00002 0x00000 0x00001 0x00002 0x00003 Page offset 0x753 0x0002 Disk 0x0006…

A: Given Virtual address is: Virtual page numbers         Page offset 0x00002 0x753   The offset…

Q: 12- In the given code, statement 2 will executed at what time step?: initial fork 5x 1'b0; //…

A: Note: Answering the first question as per the guidelines. Fork : The fork is a system call that is…

Q: 5- Assume: (CS) = 1075 H, (IP) = 0300 H, (SI) = 0100H , (DS:100H)= 00H, (DS:101H) = 10H To what…

A: Actually, CS is code segment DS is Data Segment IP is Instruction Pointer SI is Source Index DI is…

Q: In a page addressing system of 10 bits, where four bits are used for the page number, what would be…

A: A page is contiguous virtual memory which is smallest unit to store data in memory management…

Q: A computer has four page frames. The time of loading, time of last access, and the R and M bits for…

A: Introduction :Given , a table we have to find which page number will be removed , when a page fault…

Q: Consider a memory system with a cache, a main memory and a virtual memory. The access times and hit…

A: Introduction :Given , Hit rate(H) and access time(T) for cache(1) , main memory(2) , virtual…

Q: SP=1239H, SS=9876H, the ... physical address is AAAFOH O Non of them 1BC06H OAAAFH 99999H O

A: The solution for the above given question is given below:

Q: Carefully read each sentence in this question. You may agree/disagree with each sentence (consider…

A: Induction: Let all statements be separated first and give responses n justifications for them…

Q: (i) The contents of the following segment registers are as given. CS = 1111H, DS = 3333H, SS =…

A: Segmentation is the process in which the main memory of the computer is logically divided into…

Q: In symmetric multiprocessing of the computer system all processors are a. peers b. parallel c.…

A: The most common systems use symmetric multiprocessing (SMP), in which each processor performs all…

Q: Exercise: A computer has 4 frames. Page size is 2KB (2048). The loaded time, the R and M bits for…

A: so we have to calculate physical address of given virtual addresses  Which is calculated Below

Q: a) A paging system with 512 pages of logical address space, a page size of 2* and number of frames…

A:

Q: must be declared for using gcc tell linker entry point $nasm -f elf *.asm; 1d -m elf_i386 -s -o demo…

A: The code is

Q: source address to a destination address, 1 byte at a time. st = 0×5FC0, src = ®x1A10, length =…

A: It is defined as the address that is loaded into the memory-address register of the memory. A…

Q: reduces the comtention for CPU and IO services and simultaneously reduces access delays involved in…

A: _________ Reduces the contention for CPU and I/O services and simultaneously reduces access delays…

Q: In a 12-bit machine with page size of 128, we have a physical address of 1000 1001 1011. What is the…

A: Given physical address=100010011011=2203 Page size=128

Q: QUESTION 9 An 10 Address W.X.Y/Z ✓ W represents ✓ X represents ✓ Y represents ✓ Z Represents A. I…

A: The question is to select the correct options for the give question.

Q: For a microprocessor the code segment starts at 20000H, and stack segment starts at 21000H. Physical…

A:

Q: The biggest disadvantage of classfull addressing is that an address block assigned to an…

A: Let's discuss the statement : The statement is saying that biggest disadvantage of class full…

Q: Match each code segment with its description. mov ax,2 int 10h mov bx,num mov ax,[bx] indirect…

A: The question is to match each code segment with its description.

Q: witch (c) { case 1: a = 10; break; case 2: a = 20; break; case 3: a = 30; break; default: a = 0; }…

A: import data as dt data{ 'a1'=[10],            'a2' = [20],           'a3' = [30]}…

Q: Process Burst Priority P1 8 4 P2 6 P3 1 P4 2 Ps 3 3 The Avg wait in First come first served…

A: Given five processes and it's burst time and it's priority We have to calculate Average waiting time…

Q: US d PC6/RESET)} 20 23 PCO(ADCO) 24 PC1(ADC1) 25 PC2(ADC2} 26 AVCC VCC PC3(ADC3} 27 PC4(ADCA/SDA)…

A: Given that  The breadboard connection circuit diagram and it is the one of the chipset. It's…

Q: Q3) A address space is specified by 34 bit and corresponding memory space by 23 bit. 1- How many…

A: Given Data :Address space specified by 24 bitsMemory space specified by 16 bits Need to calculate…

Q: Read each sentence of this question carefully. You may agree/disagree with each sentence (treat each…

A: Let separate first all the statements to give answers n reasons for them:  “Daisy-chaining scheme…

Q: The Physical address of the String Destination Memory Reference is:       DS:DI, DS:SI, and DS:BX…

A: Given : The Physical address of the String Destination Memory Reference is:

Q: Mnemonic, Operands ADDWF 1, d ANDWF 1, d CLRF f CLAW COMF 1,d DECF f. d DECFSZ 1.d INCF 1, d INCFSZ…

A: It is defined as a low-level programming language for a computer or other programmable device…