Could someone please help me out with this question ? Thank you so much ! :) Challenge #1:Susan and Jorge stand 38 m apart. From Susan'sposition, the angle of elevation to the top of BigBen is 65°. From position, the angle of elevation tothe top of Big Ben is 49.5°. To the nearest meter,how tall is Big Ben?49.56538 m

Name: Could someone please help me out with this question ? Thank you so muc
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Description: Could someone please help me out with this question ? Thank you so much ! :) Challenge #1:Susan and Jorge stand 38 m apart. From Susan'sposition, the angle of elevation to the top of BigBen is 65°. From position, the angle of elevation tothe top of B

Answered: Challenge #1: Susan and Jorge stand 38…

Trigonometry (MindTap Course List)

8th Edition

ISBN:9781305652224

Author:Charles P. McKeague, Mark D. Turner

Publisher:Charles P. McKeague, Mark D. Turner

Chapter7: Triangles

Section7.1: The Law Of Sines

Problem 52PS: Gina is standing near a building and notices that the angle of elevation to the top of the building...

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Could someone please help me out with this question ? Thank you so much ! :)

Challenge #1:
Susan and Jorge stand 38 m apart. From Susan's
position, the angle of elevation to the top of Big
Ben is 65°. From position, the angle of elevation to
the top of Big Ben is 49.5°. To the nearest meter,
how tall is Big Ben?
49.5
65
38 m

Expert Solution

Step 1

$G i v e n, S u s a n & J o r g e s \tan d 38 m a p a r t . w h e r e C D = 38 m . F r o m S u s a n' s p o s i t i o n, C, t h e a n g l e o f e l e v a t i o n t o t o p o f b i g B e n i s 65 ° S i m i l a r l y f r o m J o r g e p o s i t i o n, t h e a n g l e o f e l e v a t i o n i s 49.5 ° L e t, A B b e t h e l e n g t h o f B i g B e n a n d A C = x U \sin g t r i g r a t i o s, \tan 49.5 ° = \frac{o p p o s i t e}{a d j a c e n t} = \frac{A B}{A D} = \frac{A B}{A C + C d} \Rightarrow \tan 49.5 ° = \frac{A B}{x + 38} \Rightarrow A B = (x + 38) \tan 49.5 ° \Rightarrow x + 38 = \frac{A B}{\tan 49.5 °} x = \frac{A B}{\tan 49.5 °} - 38 . . . . . . (1)$

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