Check that the point (1, 1, 1) lies on the given surface. Then, viewing the surface as a level surface for a function f(r, y, z), find a vector normal to the surface and an equation for the tangent plane to the sunace at (1, 1, 1). 3z - 4y + 422 = 3 vector normal = tangent plane:

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18T
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Check that the point (1, 1, 1) lies on the given surface, Then, viewing the surface as a level surface for a function f(z, y, z), find a vector normal to the surface and an equation for the tangent plane
to the sunace at (1, 1, 1).
3z - 4y? + 4z² = 3
vector normal =
tangent plane:
Transcribed Image Text:Check that the point (1, 1, 1) lies on the given surface, Then, viewing the surface as a level surface for a function f(z, y, z), find a vector normal to the surface and an equation for the tangent plane to the sunace at (1, 1, 1). 3z - 4y? + 4z² = 3 vector normal = tangent plane:
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