Check that the point (1, -1, 2) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (1, –1, 2). 3x? – 3y2 + 3z? = 12 - vector normal = tangent plane:
Check that the point (1, -1, 2) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (1, –1, 2). 3x? – 3y2 + 3z? = 12 - vector normal = tangent plane:
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18T
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