Check that the point (1, -1, 2) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (1, –1, 2). 3x? – 3y2 + 3z? = 12 - vector normal = tangent plane:

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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Check that the point (1, –1,2) lies on the given surface. Then, viewing
the surface as a level surface for a function f(x, y, z), find a vector normal to
the surface and an equation for the tangent plane to the surface at (1, –1, 2).
3x2 – 3y? + 3z2 = 12
vector normal =
tangent plane:
= Z
Transcribed Image Text:Check that the point (1, –1,2) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (1, –1, 2). 3x2 – 3y? + 3z2 = 12 vector normal = tangent plane: = Z
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