Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (−1, 1,3). 2x² − 3y² + 2z² = 17 vector normal = <-4, -6, 12> tangent plane: z = (4x+6y +26)/12

Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (−1, 1,3). 2x² − 3y² + 2z² = 17 vector normal = <-4, -6, 12> tangent plane: z = (4x+6y +26)/12

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Inner Product Spaces

Section5.1: Length And Dot Product In R^n

Problem 17E: Consider the vector v=(1,3,0,4). Find u such that a u has the same direction as v and one-half of...

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