Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (−1, 1, 3). 2x² − 3y² + 2z²: = 17

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18T
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Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a
function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at
(−1, 1, 3).
vector normal =
tangent plane:
z =
2x² − 3y² + 2z² = 17
Transcribed Image Text:Check that the point (−1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y, z), find a vector normal to the surface and an equation for the tangent plane to the surface at (−1, 1, 3). vector normal = tangent plane: z = 2x² − 3y² + 2z² = 17
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