Check the adequacy of the rigid beam to column welded connection shown. The beam is a 410 UB 53.7 of Grade 300 PLUS, the electrode is E41xx SP and (V*, M*) = (36 kN, 166 kNm). (Hint: Check the adequacy also against the minimum values required in AS4100). It M* 393
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- A bolted connection shown consists of two plates 300mm x12mm connected by 4 - 22 mm diameter bolts. Edge distances = 75mm dhole for tensile and rupture = db + 3 mm dhole for bearing strength for Lc = db + 1.5 mm Fy = 248 Mpa Fu = 400 Mpa Fn = 330 Mpa Use LRFD design method. Determine the design strength due to the gross yielding of plates. (kN)STAGGERED CONNECTIONS: A PLATE WITH WIDTH OF 400 mm AND THICKNESS OF 12 mm IS TO BE CONNECTED TO A PLATE OF THE SAME WIDTH AND THICKNESS BY 34 mm DIAMETER BOLTS, AS SHOWN IN THE FIGURE. THE HOLES ARE 2 mm LARGER THAN THE BOLT DIAMETER. THE PLATE IS A36 STEEL WITH YIELD STRENGTH Fy = 248 MPa. ASSUME ALLOWABLE TENSILE STRESS ON NET AREA IS 0.60Fy. IT IS REQUIRED TO DETERMINE THE VALUE OF b SUCH THAT THE NET WIDTH ALONG BOLTS 1-2-3-4 IS EQUAL TO THE NET WIDTH ALONG BOLTS 1-2-4. a. CALCULATE THE VALUE OF b IN MILLIMETERS. b. CALCULATE THE VALUE OF THE NET AREA FOR TENSION IN PLATES IN SQUARE MILLIMETERS. c. CALCULATE THE VALUE OF P SO THAT THE ALLOWABLE TENSILE STRESS ON NET AREA WILL NOT BE EXCEEDED.A channel shape, C8 × 18.75, is used as a tension member. The channels are bolted to a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the channel in kips, if yielding on the gross area governs? What is the ult. capacity of the channel in kips, if fracture on the net area governs? What is the ult. capacity of the gusset plate in kips, if block shear governs? What is the effective net area of the channel section, in square millimeters?
- A channel shape, C8 × 18.75, is used as a tension member. The channels are boltedto a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the channel in kips, if yielding on the gross area governs? What is the ult. capacity of the channel in kips, if fracture on the net area governs?Pls answer thank you! A flange bolt coupling has 10 steel coupling 1 inch diameter bolts evenly tighten around a 16.34 in. bolt circle. Determine the torque capacity of the connection if the allowable shearing stress in the bolt is 7.3 ksi?Three steel bolts are to be used to attach thesteel plate shown to a wooden beam. Theplate will support a 110kN and the ultimateshearing stress for the steel used is 360MPaand that a factor of safety of 3.35 is desired,determine the increase in the bolt diameterrequired if an additional 100kN load is addedto the existing 110kN.
- 8. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksih) what is the flexural rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If allowable bearing stress in holes is 1.2Fu where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 563.3 kN b. 460.8 kN c. 683. 6 kN d. 405.9 kN 2. If allowable yielding of gross area is Fy/1.67, where Fy is the yield strength of the plate and which is equal to 250 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534 kN b. 560 kN c. 446 kN d. 503 kN 3. If diameter of hole equals diameter of rivet, what is the net area of edge-3-4-edge in square millimeters? a. 2540 b. 2590 c. 2880 d. 2040an angle bar 100x100x11 mm tension member is connected with 20-mm-dia bolts as shown in the fig. both legs of the angles are connected. use fy=248 MPa and Fu=400 MPa. 1. determine the nominal strength for tensile yielding in the gross section. a. 515.59 kN b. 429.67 kN c. 545.60 kN d. 390.10 kN 2. determine the effective net area of member a. 1573 mm^2 b. 1632 mm^2 c. 1605 mm^2 d. 1815 mm^2 3. determine the nominal strength for tensile rupture in the net area. a. 642 kN b. 730 kN c. 554 kN d. 650 kN
- A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi A. Determine the Yielding Capacity of the section based on LRFD (kips) Round your answer to 2 decimal places. c. Determine the Tensile Rupture capacity of the section based on LRFD need answer pleaseThe unbraced column length of Round HSS 18 x0.5 in A500 Grade C (Fy = 50 ksi) is 30 ft.Determine the design compressive strength of the column using the equations in Chapter E inPart 16 of the AISC Manual. Confirm your answer using the AISC Manual Table 4-5 (pages 4-84,New AISCM) and (pages 4-84, New AISCM). The column has pin supports at both ends ( i.e Kx= Ky = 1.0) columns. Lx = Ly = 30 ftThe given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. Use a501 plate and a502 gr2 rivet a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivets