1011percent. Classify theusing the textural classification chart:a) Compute the percentage of clay.b). Compute the percentage of silt.c) Classify the type of soil.Problem:soil to be used as highwayClassify the givensubgrade material using the AASHTO methodby using the attached table for itsclassification.Sieve analysis % finerNo. 10 sieve = 47%%3DNo.40 sieve = 28%No.200 sieve = 9%Plasticity for the minus No. 40 fractionLiquid limit 0Plasticity index = 2%

Given, Sieve Analysis % finer Number 10 sieve = 47% Number 40 sieve = 28% Number 200 sieve = 9%…

Classify the given soil to be used ás highway subgrade material using the AASHTO method by using the attached table for its classification. Sieve analysis % finer No. 10 sieve = 47% %3D No. 40 sieve = 28% %3D No. 200 sieve = 9%

Classify the given soil to be used ás highway subgrade material using the AASHTO method by using the attached table for its classification. Sieve analysis % finer No. 10 sieve = 47% %3D No. 40 sieve = 28% %3D No. 200 sieve = 9%

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Soil engineering for highway design

Soil engineering is a part of geotechnical engineering that deals with the characteristics of soil. It also helps to understand the behavior of the soil in different conditions. The basic concepts of soil are studied to check the strength, compressibility, and porosity of the soil. This makes soil engineering an important topic for civil engineering.

Question

10
11
percent. Classify the
using the textural classification chart:
a) Compute the percentage of clay.
b). Compute the percentage of silt.
c) Classify the type of soil.
Problem:
soil to be used as highway
Classify the given
subgrade material using the AASHTO method
by using the attached table for its
classification.
Sieve analysis % finer
No. 10 sieve = 47%
%3D
No.40 sieve = 28%
No.200 sieve = 9%
Plasticity for the minus No. 40 fraction
Liquid limit 0
Plasticity index = 2%

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