Code Segment struct node { int val; struct node *Left; struct node *Right; } }; void tree_walk (struct node *x) { if(x != NULL) { } // value inside your node // left child // right child tree_walk (x->Right) printf("%d ", x->val) tree_walk (x->Left) Perform tree_walk(x) where x is the pointer to the root node. 6. What is the 1st number in the tree-walk sequence? 7. What is the 3rd number in the tree-walk sequence? 8. What is the 5th number in the tree-walk sequence? 9. What is the 7th number in the tree-walk sequence?

Code Segment struct node { int val; struct node Left; struct node Right; } }; void tree_walk (struct node *x) { if(x != NULL) { } // value inside your node // left child // right child tree_walk (x->Right) printf("%d ", x->val) tree_walk (x->Left) Perform tree_walk(x) where x is the pointer to the root node. 6. What is the 1st number in the tree-walk sequence? 7. What is the 3rd number in the tree-walk sequence? 8. What is the 5th number in the tree-walk sequence? 9. What is the 7th number in the tree-walk sequence?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Suppose the following values are inserted into a binary tree, in the order given: 12, 7, 9, 10, 22, 24, 30, 18, 3, 14, 20 Draw a diagram of the resulting binary tree. How would the values in the tree you sketched for part a be displayed in an in-order traversal? How would the values in the tree you sketched for part a be displayed in a preorder traversal? How would the values in the tree you sketched for part a be displayed in a post order traversal?
QUESTION ١ Start with an empty B-tree, draw a B-tree of order 3 created by inserting integer 1 through 15. Start with an empty B-tree, draw a B-tree of order 5 created by inserting integer 1 through 15. Remove the numbers 12 and 4 from the B-tree created in previous question in question a and b. Discuss analysis of B-tree looking at the number order and height of B-tree. Refer to the B-trees that you created in Question a and b. e. Discuss the main different between B-tree and binary search tree
PLease do A,B, and C Given the following tree: A.Is the tree balanced? If not, where is the tree out of balance? B.Is it a BST? If not, where is the violation of the search tree order? C.Show the order the nodes will be visited in a preorder, inorder, and postorder traversal. Be sure to clearly indicate which traversal is which.
a.What are the siblings of node homeworks/? b.Which nodes are in the subtree rooted at node projects/? c. What is the depth of node papers/?d. What is the height of the tree?
Question 4 Write a Lisp functions for Binary Search Tree (of numbers). (define insertTree (x tree)) returns a new tree with x inserted. (define findInTree(x tree)) return true if x is in the tree. Full explain this question and text typing work only
Assume that each node in a binary tree is distinct and that you are provided both the order in which items are discovered during a preorder traversal and a postorder traversal. What are the conditions under which you can correctly reconstruct the tree structure from these two traversal orders?
A. Draw a binary search tree based on the sequence of numbers inserted in the following order: {2, 4, 8, 6, 0, 5, 3, 9, 1, 7}. The numbers are inserted into an initially-empty binary search tree. b. Using the same sequence of numbers in Question a. draw the AVL tree. The numbers are inserted into an initially-empty AVL tree. c. From your answer for Question a. and b. discuss insertion analysis of both tree structures. Also discuss how “Lack of balance” problem solve in one of the tree. d. Assuming that the binary search tree in Figure 1 stores integer values that does not have any duplicate elements. Give the range (in the form m – n) of all values which could occupy the node ‘x’. Describe and show the step of rearranging nodes from the binary search tree in Figure 2, when the following nodes are deleted in sequence: node 5 node 63
The binary search tree is great for storing information that allows efficient searching and/or retrieval of the data. It is designed as a collection of nodes, each with a single left node/child and a single right node/child, where at each node, the left child is always less than or equal to the parent value and the right node is always greater than the parent value. To find any item in a well-balanced tree has a best case of O(log2N) retrieval. However, binary search trees have a worst-case retrieval scenario of O(N). This can happen if you have a binary search tree of the form shown here. To find the E in the search tree, we must visit all 5 nodes, not very efficient. Fortunately, it is possible to guarantee that binary search trees never end up in this unfortunate form, so that there is a better chance of having this quick O(log2N) retrieval from all binary search trees. This process is called search tree balancing. One of these techniques is to use rotations. Rotations take a…
What is the difference between a leaf tree which carries elements in its leaf vs bintree which carries elements on each node, what is the logic?
To determine the earliest common ancestor of two nodes in a binary tree, devise a method and build the necessary code. Do not add more nodes to a data structure. Not necessarily a binary search tree, please take note.
Given a binary tree and an integer S, print all the pair of nodes whose sum equals S.Note:1. Assume the given binary tree contains all unique elements.2. In a pair, print the smaller element first. Order of different pairs doesn't matter.Input format :The first line of input contains data of the nodes of the tree in level order form. The data of the nodes of the tree is separated by space. If any node does not have a left or right child, take -1 in its place. Since -1 is used as an indication whether the left or right nodes exist, therefore, it will not be a part of the data of any node.The following line of input contains an integer, that denotes the value of S.Output Format :Print each pair in a new line, as described in the task. Constraints:Time Limit: 1 secondSample Input 1:5 10 6 2 3 -1 -1 -1 -1 -1 9 -1 -115Sample Output 1:5 106 9*/.
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