Comparing sequences with a parameter For what values of adoes the sequence {n!} grow faster than the sequence {nan}?(Hint: Stirling’s formula is useful: n! ≈ √(2πn) nne-n, for large values of n.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 16E
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Comparing sequences with a parameter For what values of a
does the sequence {n!} grow faster than the sequence {nan}?
(Hint: Stirling’s formula is useful: n! ≈ √(2πn) nne-n, for large values of n.)

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