Complete a Selection sort on the following values: 2, 22, 12, 21, 3, 1 Each row is one full "pass"/"iteration" through the data:
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Complete a Selection sort on the following values:
2, 22, 12, 21, 3, 1
Each row is one full "pass"/"iteration" through the data:
![Complete a Selection sort on the following values:
2, 22, 12, 21, 3, 1
Each row is one full "pass"/"iteration" through the data:
Pass 1: [ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
Pass 2: [ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
Pass 3: [ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
Pass 4: [ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
[ Select ]
Note: the data does not have to be sorted after the forth "pass"/"iteration"
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- Quick Sort is another sorting algorithm that follows a divide-and-conquer approach. The algorithm can be summarized in 3 steps: A pivot element is chosen, usually the first element. All elements smaller than the pivot are placed to the left of the pivot. This creates 2 partitions, elements greater than the pivot and elements less than the pivot. The 2 partitions are sorted using Quick Sort. Sample code in python3: def quick_sort(arr): def quick_sort_r(arr, start, end): if end - start < 2: # single element base case return # choose a pivot pivot = start # you may choose other elements store = pivot+1 # index to store less than elements # for all elements after the pivot for i in range(pivot+1, end): if arr[i] < arr[pivot]: # if element is less than pivot arr[i], arr[store] = arr[store], arr[i] # swap store += 1 # increment store index # swap pivot with last element in less than…Assume the following list of 16 keys:18, 40, 16, 82, 64, 67, 57, 50, 37, 47, 72, 14, 17, 27, 35, 20 This list is to be sorted using Merge Sort, the number of recursive levels required to finish dividing steps this list is: 4 8 16 3the list has the following items 17 9 11 30 8 20 35 7 5 45 3 28 Apply the quick sort on the above list by using the pivot is always the left item and find the following The list after a first partition call
- Create a sort algorithm that counts the variety of key values before sorting the array using key-indexed counting using a symbol table. (This technique should not be used if there are many different key values.)Write the state of the elements of each of the following arrays after each pass of the outermost loop of the selection sort algorithm has occurred (after each element is selected and moved into place).int[] numbers1 = {63, 9, 45, 72, 27, 18, 54, 36};int[] numbers2 = {37, 29, 19, 48, 23, 55, 74, 12};True or False For each statement below, indicate whether you think it is True or False If you have an array with no “holes”, the append function performs at O(1) Inserting an element at the front and shifting all elements performs significantly worse than appending an element at the end of the list For the insert function, if the array is empty, there are no comparison operations that need to be performed and you can immediately add the new element Binary search can be used on an unsorted array to significantly improve its performance from O(n) to O(1)
- True or False For each statement below, indicate whether you think it is True or False If you have an array with no “holes”, the append function performs at O(1) Inserting an element at the front and shifting all elements performs significantly worse than appending an element at the end of the list For the insert function, if the array is empty, there are no comparison operations that need to be performed and you can immediately add the new element Binary search can be used on an unsorted array to significantly improve its performance from O(n) to O(1) Because the update algorithm depends on using linear search, its performance is O(1) in the worst case scenario True If you search for and delete an element in an unsorted array and then shift the rest of the elements to fill the hole, the worst case performance is O(n) If you search for and delete an element in an unsorted array and then move the last element to fill the hole, the worst case performance is O(n)import java.util.Scanner;import java.util.ArrayList; public class UserIDSorting {// TODO: Write the partitioning algorithm - pick the middle element as the // pivot, compare the values using two index variables l and h (low and high), // initialized to the left and right sides of the current elements being sorted,// and determine if a swap is necessarypublic static int partition(ArrayList<String> userIDs, int i, int k) {} // TODO: Write the quicksort algorithm that recursively sorts the low and // high partitionspublic static void quicksort(ArrayList<String> userIDs, int i, int k) {} public static void main(String[] args) {Scanner scnr = new Scanner(System.in); ArrayList<String> userIDList = new ArrayList<String>(); String userID; userID = scnr.next();while (!userID.equals("-1")) {userIDList.add(userID);userID = scnr.next();}// Initial call to quicksort quicksort(userIDList, 0, userIDList.size() - 1); for (int i = 0; i < userIDList.size(); ++i)…If the list has the following items 17 9 11 30 8 20 35 7 5 45 3 28 Apply the quick sort on the above list by using the pivot is always the left item and find 1.The split point in the second partition call.
- If the list has the following items 17 9 11 30 8 20 35 7 5 45 3 28 Apply the quick sort on the above list by using the pivot is always the left item and find the following The list after a first partition call 2-The split point in the second partition callslecetion sort (python) Selection sort is a sorting algorithm, like Bubble sort which you saw in the previous module. Selection sort works as follows: Selection sort divides the input list into two parts: a sublist of sorted items (left part) and a sublist of still unsorted items (right part). Initially, the sorted sublist is empty and the whole input consists of the unsorted sublist. To fill the sorted sublist, the algorithm computes the (index of) the minimum of the unsorted sublist and swaps the first unsorted element and the minimum element (if the minimum is already the first element, nothing happens). Afterward, the sorted sublist is one bigger. This continues until the unsorted sublist is empty and the entire input is sorted. Example: Sorted sublist Unsorted sublist Least element in unsorted list () (11, 25, 12, 22, 64) 11 (11) (25, 12, 22, 64) 12 (11, 12) (25, 22, 64) 22 (11, 12, 22) (25, 64) 25 (11, 12, 22, 25) (64) 64 (11, 12, 22, 25, 64) () Implement this…Modify the following program to read dictionary items from a file and write the inverted dictionary to a file: characters = {'Bugs':['Rabbit', 1940, 'boy'], 'Garfield': ['Cat', 1978, 'boy'], 'Tweety': ['Bird', 1942, 'girl'], 'Sandy': ['Squirrel', 1999, 'female']} print("Printing the original dictionary") print(characters) print("") def invert_dict(characters): inverse = dict() for key in characters: val = characters[key] for list_item in val: if list_item not in inverse: inverse[list_item] = [key] else: inverse[list_item].append(key) return inverse my_invert = invert_dict(characters) print("Printing the inverted dictionary") print(my_invert) Include the following: 1) The input file for your original dictionary (with at least six items).2) The Python program to read from a file, invert the dictionary, and write to a different file.3) The output file for your inverted dictionary.…
