Complete the following leveling noteand determine the elevation ofBM14. Apply arithmetic checking.STATION BS FS ELEVATICBM124.64209.6515.80 5.0622.25 5.0236.02 5.8548.96 4.348.06 3.229.45 3.71712.32 2.02ВМ141.98

It is calculated by using height of instrument method Height of instrument = elevation + BS…

Answered: complete the following leveling nột and…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given the closed traverse data. Lines Bearing Distance AB N20o E 20.35 BC N68oE 18.75 CD S22oE 21.30 DE S40oW 13.35 EF S62oW 9.23 FA Compute the following. Compute the bearing and distance of line FA Compute the area of the given traverse
Reciprocal leveling between points A and B, located on opposite banks of a wide river gives the following readings in meter. From the first setup near A; on A, 0.993; on B, 2.076, 2.077, and 2.078. For the set up near B the readings are; on B 2.549; on A; 1.463, 1.462, and 1.463. If the elevation of A is 925.28 meters determine the elevation of B
Reciprocal leveling between points A and B, located on opposite banks of a wide river gives the following readings in meters. From the first setup near A: on A, 0.993; on B, 2.076, 2.077, and 2.078. For the set-up near B the readings are: on B, 2.549; on A. 1.463, 1.462, and 1.463. If the elevation of A is 925.28 meters determine the true difference in elevation between the two points and the elevation of B
Fundamentals of Surveying In leveling across a river, reciprocal level readings were taken between two points A & B. From a set-up near A on A, 0.954 &0.952m, on B 2.086, 2.087, 2.088 & 2.087 m. At the setup near B: on B, 2.450 and 2.448m, on A, 1.362, 1.363, 1.364 & 1.363m What the Elevation at B if Elev at A is 45.75m?
1. A triangular piece of land ABC (clockwise) has the following directions in azimuth fom South. AB = 225o23’, BC = 325o20’, CA = 100o10’ Compute the interior angles. 2. An open traverse ABCDE has following azimuth from South: AB = 250o30’ BC = 280o20’ CD= 210o45’ DE = 150o50’ Required: Deflection angles at points B,C, and D. Draw the figure properly.
A transit with a stadia constant equal to 0.30 is used to determine the horizontal distance betweeen points B and C, with a stadia intercept reading of 1.75 m, the distance BC is equal to 185.87m. Using the same instrument, it was used to determine the difference in elevation between B and D having a stadia intercept reading of 2.42 m at D at a vertical angle of (+) 6-30-00. Compute the difference in elevation of B and D. a.26.91 b. 28.90 c. 22.78 d. 23.78
a.) Using the Stadia Reduction Table,what is the difference in elevation if the observedvertical angle is 19⁰24''?b.) Using the Stadia Reduction Table,what is the horizontal distance if the observedvertical angle is -7⁰14''?c.) Using the Stadia Reduction Table,what is the Chd if the instrument constant is 0.381and the observed vertical angle is -16.80⁰?
Differential leveling was performed to run the elevation of BM 3-1 located 30.00 meters to the right of station 3 + 480, to BM 3-2 located 27.50 m to the left of station 3 + 920.00. Calculate the elevations of the points and verify the quality of the annotations in the level book. STATION BS HI FS ELEVATION (m) BM 3-1 1.458 328.954 TP - 1 2.256 2.314 TP - 2 1.382 3.127 TP - 3 3.456 2.171 TP - 4 0.759 1.282 BM 3-2 2.000
For all the computed values with decimals, use four (4) digits after the decimal. Differential leveling runs from BM10 to BM11 at a distance of 7.5 km. It was observed that the leveling rod was inclined 6° from the vertical every time the backsight is taken. The average BS reading is 3.15m and the average length per set-up is 300m. Determine the error every 300m set-up and the correct elevation of BM11 if the recorded elevation was 173.20m.
Reciprocal leveling gives the following readings in meters from a setup near A: on A, 1.365; on B, 4.928, 4.924, and 4.926. At the setup near B: on B, 4.251; on A,1.687, 1.688, and 1.688. The elevation of A is 564.872 m. Determine the disclosure and elevation of B.
prove the formula of the combined correction for earths curvature and refraction Hcr = 0.0675 D^2 where: Hcr= combined correction D = horizontal distance
Determine the elevation of BM12 using double rodded leveling and sketch it. Tabulate it in a table

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complete the following leveling nột and determine the elevation of BM14. Apply arithmetic checking. STATION BS FS ELEVAT BM12 4.64 209.6 1 5.80 5.06 2.25 5.02 3 6.02 5.85 4 8.96 4.34| 8.06 3.22 9.45 3.71 7 |12.32 2.02 BM14 1.98