Complete the if-else statement to print 'LOL means laughing out loud' if user_tweet contains 'LOL' Sample output with input: 'I was LOL during the whole movie!" LOL means laughing out loud.
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Q: Complete the if-else statement to print 'LOL means laughing out loud' if user_tweet contains 'LOL'.…
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Is there a way to make an abbreviation using if else statement in pyhton there's a sample below
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- Write a program that prompts the user to input a positive integer, andthen calculates and displays the product of odd integers from 1 to thatnumber inclusive. The program will use the for statement to perform thecalculation. C++ please.int main(){ if(var1>50) { num = 20.0 } else { if(var1>35) ---- Line 7 { num= 35.0; } else if (var1<80) { num=60.0; } else { num=40.0; }} What should be the outcome of the condition in line 7 in order for the value of num to be equal to 60.0?Write the correct statement to store value of “vb programming” to label button 5 Select one: a. lbl_label5 = “vb programming” b. “vb programming” = lbl_button5 c. lbl_button5 = “vb programming” d. lbl_button5.text = “vb programming” What is the output of the given program below if the inputted values are both 2 #include<stdio.h>#include<conio.h>void main(){int num1,num2,ans;print(“Input First number: “);scanf(“%d”,&num1);print(“Input Second number: “);scanf(“%d”,&num2);ans=num1+num2;switch(ans){case 2: printf(“HAHAHA”); break;case 4: printf(“HOHOHO”); break;case 6: printf(“HEHEHE”); break;default: printf(“INVALID”);}getch();}
- Correct the following code so that it prints the correct message. if (score <= 60)cout << "Pass" << endl;else;cout << "Fail" << endl;Correct the following code so that it prints the correct message.if (score <= 60)cout << "Pass" << endl;else;cout << "Fail" << endl;C++ Write a program that asks for the starting time and the number of minutes of the call, and displays the charges. The program should ask for the time to be entered as a floating-point number in the form HH.MM. For example, 07:00 hours will be entered as 07.00, and 16:28 hours will be entered as 16.28. Input Validation The program should not accept times that are greater than 23:59. Also, no number whose last two digits are greater than 59 should be accepted. Hint: Assuming num is a floating-point variable, the following expression will give you its fractional part: num – static_cast<int>(num);
- Prompt the user to enter in the three number that define a quadratic ??2+??+?=0ax2+bx+c=0, that is prompt the user to enter in numbers a, b, c. Compute the two solutions to the quadratic (i.e., solve for x). We will assume the user inputs numbers that result in a positive discriminant. Display the results.Re-write the following program by converting IF-ELSE statement to SWITCH statement. #include<iostream>Using namespace std;#include<iostream>using namespace std;int main(){char grade;cout<<"Enter student's grade: ";cin>>grade;if (grade=='F')cout<<"Student marks less than 40 and Fail";else if (grade=='E')cout<<"Student marks less than 50 and Pass";else if (grade=='D')cout<<"Student marks less than 60 and Pass";else if (grade=='C')cout<<"Student marks less than 70 and Pass";else if (grade=='B')cout<<"Student marks less than 80 and Pass";else if (grade=='A')cout<<"Student marks less than 100 and Pass";elsecout<<"Wrong grade entered \n";return 0;}(Misc. application) a. Write a program to reverse the digits of a positive integer number. For example, if the number 8735 is entered, the number displayed should be 5378. (Hint: Use a do statement and continuously strip off and display the number’s units digit. If the variable numinitially contains the number entered, the units digit is obtained as (num % 10). After a units digit is displayed, dividing the number by 10 sets up the number for the next iteration. Therefore, (873510)is5and(8735/10)is873. The do statement should continue as long as the remaining number is not 0.) b. Run the program written in Exercise 3a and verify the program by using appropriate test data.
- Convert the following program by changing conditional operator to if-else statement.#include<iostream>using namespace std;int main(){int Var1, Var2, Var3=10;cout<<”Enter the first number\n”;cin>>Var1;cout<<”Enter the second number\n”;cin>>Var2;(Var1<Var2)? Var3=100 : Var2=100;cout<”Var2: ”<<Var2<< and <<”Var3: ”<<Var3;return 0;}The factorial of n is the product of all the nonnegative integers from 1 to n. for 8! = 1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 = 40, 320 Write a program that prompts the user to input a nonnegative integer (if yc negative integer, the program should prompt you to re-enter until you nonnegative integer) and calculate the factorial of that number. Your result should look like below: Enter a nonnegative integer: 8 The factorial of 8 is 40320.using javaUser in Below the complete statement.