Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side. sec z - cot z - 1= cot?z Steps: sec z- cot? z - 1 = cotz

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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There are 3 steps THIS IS NOT A GRADED QUESTION
3:02 )
O * X 4G
al 44%
...
illeenisd.schoology.com
3
May 10: STUDY GUIDE: Unit 10- Trig Identities
5 of 10
Complete the steps by applying trig identities to show
that the left hand side of the equation is equivalent to
the right hand side.
ser - cot? z –1 = cot? r
Steps:
sec? - cot? x – 1
= cot2 r
cos' z
sin
: (1 - sin a) - sin' z
cos'
enta
coe
cus I
sin I
1 cos z. sin
cusa
1
1
: csc" a - 1
COS
1
cos a (sin a cos'
c sina
sin
: cos a+ sin r. Bin
: cos 2
1
sin x
ein'r
sin e
Next
HAC
НАС
II
+
Transcribed Image Text:3:02 ) O * X 4G al 44% ... illeenisd.schoology.com 3 May 10: STUDY GUIDE: Unit 10- Trig Identities 5 of 10 Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side. ser - cot? z –1 = cot? r Steps: sec? - cot? x – 1 = cot2 r cos' z sin : (1 - sin a) - sin' z cos' enta coe cus I sin I 1 cos z. sin cusa 1 1 : csc" a - 1 COS 1 cos a (sin a cos' c sina sin : cos a+ sin r. Bin : cos 2 1 sin x ein'r sin e Next HAC НАС II +
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