Complete the swap algorithm to swap the first two values in an array. Assume the array is an array of integers. //fill in here A[0] A[1]; A[1] temp; %3D temp=A[0];
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Question 5
0/1 pts
Complete the swap algorithm to swap the first two values in an array.
Assume the array is an array of integers.
//fill in here
A[0]
A[1];
A[1]
temp;
temp=A[0];](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2abc661b-c0c9-4b79-9347-0fc323cf483e%2Faa6bf1c5-e6a3-45ca-84c1-7044abfc7660%2Fxbr5sxb_processed.png&w=3840&q=75)
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- Use C++ Programming bool remove(const char* person) Improve the remove method where you return true if an entry is successfully deleted (i.e. we have found an entry that matches the person), otherwise return false. Initial code below bool remove(const char* person) { for (int i = 0; i < index; i++) { entry* existing = array + (sizeof(entry) * i); if (!strcmp(existing->name, person)) { // MOVE all entries to the left starting to the next // We are to stop before we reach index-1 so as not to reach index-1+1 where data doesn't exist for (int j = i; j < index - 1; j++) { // current entry = next entry *(array + ( sizeof(entry) * (j) ) ) = *(array + ( sizeof(entry) * (j+1) ) ); } index--; break; } } // Added temporarily. You may delete or move this.…The code below computes the intersection (the number of entries shared by two arrays). It is assumed that neither array contains any duplicates. It computes the intersection by sorting one array (array b) and then iterating over array a to see if each value is in b (through binary search). What is its duration? nt intersection(int[] a, int[] b) {mergesort(b);}int intersect = 0;for (int x : a) {if (binarySearch(b, x) >= 0) {intersect++;return intersect; }}4. Write a program to find kth smallest element in unsorted array?You are given an unsorted array of numbers and k, you need to find the kth smallest number in the array. Forexample if given array is {1, 2, 3, 9, 4} and k=2 then you need to find the 2nd smallest number in the array,which is 2.
- Java Quick Sort but make it read the data 10, 7, 8, 9, 1, 5 from a file not an array // Java implementation of QuickSort import java.io.*; class GFG { // A utility function to swap two elements static void swap(int[] arr, int i, int j) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } /* This function takes last element as pivot, places the pivot element at its correct position in sorted array, and places all smaller (smaller than pivot) to left of pivot and all greater elements to right of pivot */ static int partition(int[] arr, int low, int high) { // pivot int pivot = arr[high]; // Index of smaller element and // indicates the right position // of pivot found so far int i = (low - 1); for (int j = low; j <= high - 1; j++) { // If current element is smaller // than the pivot if…1. Sorting• Begin by filling an array with random numbers:import numpy as npnp.random.seed(1012)DATASIZE = 1000MAX_VALUE = 10000000data = np.random.randint(0, MAX_VALUE, size=DATASIZE)• Write a function that is passed a numpy array. The function should walkthrough the array element-by-element, comparing the current element tothe next element. Swap if the next is smaller than the current – sortingthese two elements.• Write a second function that calls the above function n times, where n isthe number of elements (size) of the array. Pass the same numpy arrayeach time. 2. Bubble Sort• The sort from part 1 can be improved. If the data passed to be sorted isalready sorted, it still performs all of the work, as if the array was notsorted.Make two improvements:• Change the first function (the one that does the comparisons), so that it returns aboolean that states whether the array is sorted. Make use of that boolean to stopcalling the first function if the array is sorted.• Consider…1. Sorting• Begin by filling an array with random numbers:import numpy as npnp.random.seed(1012)DATASIZE = 1000MAX_VALUE = 10000000data = np.random.randint(0, MAX_VALUE, size=DATASIZE)• Write a function that is passed a numpy array. The function should walkthrough the array element-by-element, comparing the current element tothe next element. Swap if the next is smaller than the current – sortingthese two elements.• Write a second function that calls the above function n times, where n isthe number of elements (size) of the array. Pass the same numpy arrayeach time.
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