Compute the area of the given traverse using DPD and DMD method.
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A: I already uploaded this answer so ,in this I am just making few changes.
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Provide a separate table for DMD and DPD. Also, before the bearing, compute for the azimuths
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- A closed traversed has the following data. LINE DISTANCE BEARING AB 185.33 N 43 E BC 258.28 S 67 E CD ? S 38 W DE ? S 81 W EA 150.87 N 27 W The summation of the latitude and departure of the traverse are -26 and 55, respectively. Using COMPASS RULE, determine the follwowing:(Round off into four decimal places)WHAT IS THE LENGTH OF THE LINE CD?PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) ANSWER HERE IS: Azimuth EA=149.300278 PROBLEM 2 Compute the linear misclosure for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.)Round off your answer to three decimal places. No need to include the unit. ANSWER HERE IS: 0.065 NEEDED TO ANSWER im confuse Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse in Problem 1 considering the length of Problem 2. If the coordinates of station A are X = 20,000 ft and Y = 15,000 ft, calculate x coordinates of course DE.A closed traverse has the following data: Course Length Bearing Interior Angle to the Right AB 125.98 N42°15′E A = 112°07′ BC 75.25 N35°20′W B = 102°25′ CD 80.34 S74°44′W C = 110°04′ DE 112.68 S19°56′W D = 125°12′ EA 78.35 S69°52′E E = 90°12′ a.) Adjust the traverse using transit rule. b.) Compute the area (m2) of the traverse using DPD method.
- A 5-sided closed traverse that needs correction has the following distances and azimuths:AB = 285.10 m <26°10'BC = 610.45 m <104°35'CD = 720.48 m <195°30'DE = 203.00 m <358°18'EA = 647.02 m <306°54'PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) NEEDED ANS: Compute the relative precision for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.) Round off the denominator to two decimal places.A closed traverse has the following bearings. OBSERVED BEARINGS LINE FORWARD BACK AB N 55°30’ E S 55°45’ W BC S 58°40’ E N 58°30’ W CD S 14°30’ E N 14°00’ W DE S 77°10’ W N 77°10’ E 0EA N 40°20’ W S 40°15’ E Adjust the following bearings in order to close the traverse. Also draw the corrected traverse.
- PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) NEEDED TO ANS Compute the linear misclosure for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.) Round off the answer to three decimal placesProblem #1 For the given data of a close traverse, determine the missing bearings of courses DE and EF then solve the AREA using DPD. Sketch the traverse. LINES DISTANCE (m) BEARING AB 60 S 49⁰16’ E BC 59 S 67⁰48’ E CD 95 N 32⁰28’ W DE 110 ? EF 128 ? FA 71 S 18⁰56’ EA five-sided closed field traverse has the following angles: A= 99°23'07", B=151°13'02", C=80°58'30", D=115°19'02", E=93°05'39". The lengths of the sides are as follows: AE 352.72m, ED 582.01m, DC 367.19m, CB 381.48m, BA 401.41m. Determine the traverse's closure, accuracy, and area. The bearing of Line AB is N 51°32’0” E. Determine the bearing of Line EA.
- A closed traverse has the following data. Compute the bearing of line AB. a. N53.57°E b. N27.04°E c. N25.76°W d. N55.67°WA closed field traverse has the following lengthsAB = 636.45; BC = 654.49; CD = 382.85; and DA = 512.77.The interior angles are as follows (measured as angles to the right):A = 81º 23'; B = 72º 33'; C = 89º 40'; and D =116º 24'.The bearing of AB is S 33º 19' W and the side BC is in theSE quadrant.a) Which is the bearing of line CD? b) Which is the bearing of line BC?c) Which nearly gives the value of LEC?Choose the correct ansS 65deg 18min ES 74deg 08min Es 48deg 04min WN 15deg 32EA closed field traverse has the following lengthsAB = 636.45; BC = 654.49; CD = 382.85; and DA = 512.77.The interior angles are as follows (measured as angles to the right):A = 81º 23'; B = 72º 33'; C = 89º 40'; and D =116º 24'.The bearing of AB is S 33º 19' W and the side BC is in theSE quadrant.a) Which is the bearing of line CD? b) Which is the bearing of line BC?c) Which nearly gives the value of LEC?