Compute the code that return the matrix M = AT A for a given matrix A - the superscript T denoted the transpose. I have started the code for you, which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of the loops involved. 1: # perform and return the multiplication of $A^TA$ import numpy as np def multiply_At_A (A): # these lines set up the correct dimensions of the returned matrix. # the matrix A is of dimension dim1 x dim2 - # the matrix A^T (transpose of A) is dim2 x diml # the matrix (A^T A) is of dimension dim2 x dim2 I dim1= A.shape [0] dim2 = A.shape [1] matrix = np.zeros([dim2, dim2]) for i in range (dim2): for j in range (dim2): # complete the final loop to compute matrix[i,j] #YOUR CODE HERE return matrix
Compute the code that return the matrix M = AT A for a given matrix A - the superscript T denoted the transpose. I have started the code for you, which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of the loops involved. 1: # perform and return the multiplication of $A^TA$ import numpy as np def multiply_At_A (A): # these lines set up the correct dimensions of the returned matrix. # the matrix A is of dimension dim1 x dim2 - # the matrix A^T (transpose of A) is dim2 x diml # the matrix (A^T A) is of dimension dim2 x dim2 I dim1= A.shape [0] dim2 = A.shape [1] matrix = np.zeros([dim2, dim2]) for i in range (dim2): for j in range (dim2): # complete the final loop to compute matrix[i,j] #YOUR CODE HERE return matrix
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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SARR AS O P in (R QC CXNNN
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Python 3 (ipyke
Compute the code that return the matrix M = AT A for a given matrix A - the superscript T denoted the transpose. I have started the code for you,
which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of the loops involved.
1: # perform and return the multiplication of $A^TA$
import numpy as np
def multiply_At_A (A):
# these lines set up the correct dimensions of the returned matrix.
# the matrix A is of dimension dim1 x dim2 -
dim1= A.shape [0]
dim2 = A.shape [1]
matrix = np.zeros([dim2, dim2])
# the matrix A^T (transpose of A) is dim2 x diml
# the matrix (A^T A) is of dimension
dim2 x dim2
I
return matrix
X
Python_coursework.ipynb X +
for j in range (dim2):
# complete the final loop to compute matrix[i,j]
# YOUR CODE HERE
: ## Don't write any code in this box
1: ## Don't write any code in this box
ww
P lin (2
Mem:
№ ni](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F226fee03-c629-4185-8cef-0e29840a7a8d%2Fab349343-2771-46a4-918d-3c2a3ff7dece%2Fguwh5pf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1 BAWIn B S
ser/ex22399/lab
Tabs Settings
Settings
ncher
&
Help
SARR AS O P in (R QC CXNNN
V
for i in range (dim2):
X
Assignments
1
■ с
Code
Validate
Python 3 (ipyke
Compute the code that return the matrix M = AT A for a given matrix A - the superscript T denoted the transpose. I have started the code for you,
which gets the dimension of the matrix, and creates the zero matrix of the correct size. I have also provided some of the loops involved.
1: # perform and return the multiplication of $A^TA$
import numpy as np
def multiply_At_A (A):
# these lines set up the correct dimensions of the returned matrix.
# the matrix A is of dimension dim1 x dim2 -
dim1= A.shape [0]
dim2 = A.shape [1]
matrix = np.zeros([dim2, dim2])
# the matrix A^T (transpose of A) is dim2 x diml
# the matrix (A^T A) is of dimension
dim2 x dim2
I
return matrix
X
Python_coursework.ipynb X +
for j in range (dim2):
# complete the final loop to compute matrix[i,j]
# YOUR CODE HERE
: ## Don't write any code in this box
1: ## Don't write any code in this box
ww
P lin (2
Mem:
№ ni
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