Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 0 3 2 4 3 0 4 - 1 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is (3)(– 16) - (0)(- 2) + (3)(8) = O B. Using this expansion, the determinant is (0)( – 2) – (4)( - 3) + (4)(3) =| Oc. Using this expansion, the determinant is - (3)(- 16) + (0)(- 2) - (3)(8) =| O D. Using this expansion, the determinant is - (0)(- 2) + (4)(– 3) – (4)(3) =

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column.
3 0
3
2 4
3
0 4
- 1
Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answer.)
O A. Using this expansion, the determinant is (3)(– 16) - (0)(- 2) + (3)(8) =
O B. Using this expansion, the determinant is (0)( – 2) – (4)( - 3) + (4)(3) =|
Oc. Using this expansion, the determinant is - (3)(- 16) + (0)(- 2) - (3)(8) =|
O D. Using this expansion, the determinant is - (0)(- 2) + (4)(– 3) – (4)(3) =
Transcribed Image Text:Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 3 0 3 2 4 3 0 4 - 1 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is (3)(– 16) - (0)(- 2) + (3)(8) = O B. Using this expansion, the determinant is (0)( – 2) – (4)( - 3) + (4)(3) =| Oc. Using this expansion, the determinant is - (3)(- 16) + (0)(- 2) - (3)(8) =| O D. Using this expansion, the determinant is - (0)(- 2) + (4)(– 3) – (4)(3) =
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