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A: I am attaching image so that you understand each and every step.
Q: A region bounded by f(x) = 3 − x, y = 0, and x = 0 is shown below. Find the volume of the solid…
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![Compute the double integral ff(6zy2 +12z³y + 4y) da dy with R= 3,5 z [1,2].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9da8bf3-a2eb-4f8f-85fc-2c74ffb8690a%2F5f6362f6-f71a-4024-bad3-43e2f7bf9273%2Fhm7uhyc_processed.jpeg&w=3840&q=75)
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- I don't understand why the double integral of z dA over region D turns into [(64-4r^2)^(1/2)-(-(64-4r^2)^(1/2)]rdrdtheta, instead of just (64-4r^2)^(1/2) rdrdtheta since R {(r,theta) | 0 <= r <= 2; 0 <= theta <+ 2pi}.Evaluate the triple integralE 7xdV, where E is bounded by the paraboloid x = 7y2 + 7z2 and the plane x = 7.Evaluate the triple integral. E 8x dV, where E is bounded by the paraboloid x = 5y2 + 5z2 and the plane x = 5