READER to te readerlD rd001 rd002 firstname address bp20 po box 40 Limbe bp45 bp67 bp30 bp9 bp70 bp80 bp09 bp76 surname MATINES MALET town sex Jones Limbe Male Peters Male Female Female rd003 rd004 rd005 rd006 rd007 rd008 rd009 rd010 ТEGHEN Rose Buea NGALA ТАВА TAFAC NANFACK NKEMKANG KAHMBANG joshua ABINI Tiko Ndop Nkwen bafousam bafousam Tiko batibo Joan Malam Vincent geogia john Male |Male Female Male Male Female beatrice LOAN readerID datetaken datedue rd001 rd005 rd001 rd002 rd004 rd004 rd010 bookID lib001 lib003 lib004 lib002 lib006 lib005 lib008 5/9/2013 10/9/2013 8/6/2012 1/3/2013 5/9/2013 9/9/2013 8/8/2013 9/10/2013 7/7/2012 10/8/2013 2/5/2013 8/6/2013 9/10/2013 10/15/2013

READER to te readerlD rd001 rd002 firstname address bp20 po box 40 Limbe bp45 bp67 bp30 bp9 bp70 bp80 bp09 bp76 surname MATINES MALET town sex Jones Limbe Male Peters Male Female Female rd003 rd004 rd005 rd006 rd007 rd008 rd009 rd010 ТEGHEN Rose Buea NGALA ТАВА TAFAC NANFACK NKEMKANG KAHMBANG joshua ABINI Tiko Ndop Nkwen bafousam bafousam Tiko batibo Joan Malam Vincent geogia john Male |Male Female Male Male Female beatrice LOAN readerID datetaken datedue rd001 rd005 rd001 rd002 rd004 rd004 rd010 bookID lib001 lib003 lib004 lib002 lib006 lib005 lib008 5/9/2013 10/9/2013 8/6/2012 1/3/2013 5/9/2013 9/9/2013 8/8/2013 9/10/2013 7/7/2012 10/8/2013 2/5/2013 8/6/2013 9/10/2013 10/15/2013

Np Ms Office 365/Excel 2016 I Ntermed

1st Edition

ISBN:9781337508841

Author:Carey

Publisher:Carey

Chapter7: Developing An Excel Application

Section: Chapter Questions

Problem 3RA

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Review the following program that extracts the email server domain name. >>> data = 'From stephen.marquard@uct.ac.za Sat Jan 5 09:14:16 2008 ' >>> atpos = data.find('@') >>> print(atpos) 21 >>> sppos = data.find(' ',atpos) >>> print(sppos) 31 >>> host = data[atpos+1 : sppos] >>> print(host) 1. Adapt the program to extract the user name (stephen.marquard) and Copy+Paste the code in the answer2. Run the adapted program and include a full window screenshot with system time and date in the answer.
Please use IBM Business Computing to answer the folloing question 1 – Create a new Library called VnnLIB1 (NN is your student login id number) using the command CRTLIB 2 – Create a new Jobq VnnJOBQ1 and Outq VnnOUTQ1 in the Library VnnLIB1 using the command crtjobq and crtoutq 3 – Grant *PUBLIC *USE Authority to your VnnLIB1 library using the command wrkobj VnnLIB1 and then option 2 4 – Submit 3 jobs using sbmjob in your VnnJOBQ1, these jobs will not run, since they are not attached to any sub-system. Check it out by using wrkjobq command 5 – Change the 3 jobs submitted in step #4 to run in sub-system QINTER and change the out to VnnOUTQ1. These jobs will run, and the results will be in VnnOUTQ1. Check it out by using wrkoutq command 6 – Create a new Source File called VnnSRC in your library VnnLIB1 using command crtsrcpf 7 - Create a new Save File called VnnSAVF in your library VnnLIB1 using command crtsavf 8 – Run DSPJOBLOG command and save the output in your spool file 9 – Write the…
How to fix the problem below: Parser Error Description: An error occurred during the parsing of a resource required to service this request. Please review the following specific parse error details and modify your source file appropriately.Parser Error Message: Could not load type 'bse21aftmoviestore.tutorials.week2.datetimeex1'.Source Error: Line 1: <%@ Page Title="" Language="C#" MasterPageFile="~/usermaster.Master" AutoEventWireup="true" CodeBehind="datetimeex1.aspx.cs" Inherits="bse21aftmoviestore.tutorials.week2.datetimeex1" %> Line 2: <asp:Content ID="Content1" ContentPlaceHolderID="head" runat="server"> Line 3: </asp:Content> Source File: /tutorials/week2/datetimeex1.aspx Line: 1 The code used is: <asp:Content ID="Content1" ContentPlaceHolderID="head" Runat="Server"><script runat="server">void Page_Load(){lblServerTime.Text = DateTime.Now.ToString();}</script></asp:Content><asp:Content ID="Content2"…
Please identify the correct statement(s) for the following code snippet from the script: while inst_iter.hasNext() and not monitor.isCancelled(): ins = inst_iter.next() addr = ins.getAddress() pcodeList = ins.getPcode() for pcode in pcodeList: if pcode.getOpcode() == PcodeOp.FLOAT_DIV or pcode.getOpcode() == PcodeOp.INT_DIV: print("Address: {}, Inst: {}, Pcode: {}".format(addr, ins, pcode)) addrSet.add(addr) Question 1 options: It saves the address of the disassembled instruction that introduces division. This snippet uses refined/high p-code. This snippet uses raw p-code. It uses p-code opcode to identify the division operator. It uses the mnemonic string of a disassembled instruction to identify the division operator. It saves the sequence number of the p-code instruction that introduces division.
can you please explain this code which is written to perform these tasks: The list of projects that each employee worked on. The average award received by each employee. The maximum and minimum monthly awards are received by each employee. The project id and language in which each employee received the maximum award for working on that project. The employee name that received the maximum awards within 10 years. The number of projects that each employee did not work on it. code: import pandas as pd import numpy as np URL = "https://bit.ly/38zhU5T" df=pd.read_csv(URL) arr=df.to_numpy() employee_notworked=[0,0,0,0] #Array to store the number of projects each employee did not work employee=[[]]*4 #list of projects worked by employees. min_award=[0,0,0,0] #Array to store minimum award received by employees. max_award=[0]*4 #Array to store maximum award received by employees. avg_awards=[0]*4 #Array to store the average award received by employees. maxaward_employee=0 project_id=[None]*4…
if [ $(id -u) -eq 0 ];then read -p "enter username:" username read -s -p "enter password:" password egrep "^$username"/etc/passwd>/dev/null if [ $? -eq 0];then echo "$username exists!" exit 1 else pass=$(perl -e 'print crypt($ARVG[0], "password")' $password) useradd -m -p "$pass" "$username" [ $/ -eq 0 ] && echo "user has been added to system!" || echo "Failed to add a user!" fi else echo "Only root may add to the system" exit 2 fi * recheck the code if this is valid syntax for account management or suggest /do another user account management shell script that runs in unix terminal and please attache the output at the end
myBytes BYTE 10h,20h,30h,40hmyWords WORD 8Ah,3Bh,72h,44h,66hmyDoubles DWORD 1,2,3,4,5myPointer DWORD myDoubles
Please complete this code for the attache question: List P = 16F877A PORTA EQU h'05'TRISA EQU h'85'PORTC EQU h'07'TRISA EQU h'87'STATUS EQU h'03' BSF STATUS,5MOVLW h'FF'MOVWF TRISCCLRF TRISABCF STATUS,5 ... ... .. END
Create an MVC applicationthat works on super-global variables and sends an email to the user after the user submits the information on the landing page. This information can be the user’s personal information.
Computer Science Create a session variable called SProot and assign the generated positive root valueto it in Oroots.php. Display this session variable in PosRoot,php page.
Create the algorithm for the C++ code presented below that shows step-by-step procedures for solving the problem. the code can be found at the URL: https://system.tips/text/view?q=uaaeqhxt
The delivery drones have a internal reporting and logging system thatrecords events and issues during flights. These logfiles contain the last 1000events/messages as well as their status codes.The Logfile FormatBy default, the logfiles are all called ‘logfile.txt’. Each logfile is exactly 1000 lineslong.Each entry in the file consists of 4 fields:1. a line number (starting at 0)2. a POSIX timestamp3. a message/event type4. an event descriptionEach field (line number, timestamp etc.) is separated by a space, except for thedescription which ends with a full stop.Log events come in three different types: NOTIFY, WARNING, and ERROR. Task 1: Display Because the logfiles are so big, we would only like to display a certain number oflines at a time. We prompt the user to choose start and end line numbers andprint all the lines from start to end (inclusive).The input constraints are as follows: 0 start end 999You can safely assume that the inputs will fall within that…