Question
Asked Jun 28, 2019
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Condense the expression to the logarithm of a single quantity

(c) 4 [lnz +ln(z +5)] −2ln(z −5)

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Expert Answer

Step 1

Consider the provided expression.

4In +In ( +5)-2 In(-5)
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4In +In ( +5)-2 In(-5)

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Step 2

Properties of logarithm:

Property 1: In (xy) = Inxny
x
Inx - n y
Property 2: In
Property 3: In r' = y lnx
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Property 1: In (xy) = Inxny x Inx - n y Property 2: In Property 3: In r' = y lnx

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Step 3

Now use the above property to solve the provided expressio...

4In In52 ln(-5)
4n +4n(5-2 ln (z -5)
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4In In52 ln(-5) 4n +4n(5-2 ln (z -5)

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Algebra

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