Connor was asked to solve the problem 39+25 twice, the first time when the problem was in a context of baseball cards, and the second time when the problem was not in a context. When Connor solved the problem the second time he described the process in these steps: 30+20 = 50 5+5+50 = 60 4+60 = 64 In the second step, how did Connor come up with adding 5+5 to 50? A. He made a mistake but still happened to find the correct sum. B. He decomposed the nine from 39 into five and four, and then added the five to the five from 25. C. He knew that nine and five was 14, which can be decomposed into 5+5+4. D. None of the above.
Connor was asked to solve the problem 39+25 twice, the first time when the problem was in a context of baseball cards, and the second time when the problem was not in a context. When Connor solved the problem the second time he described the process in these steps: 30+20 = 50 5+5+50 = 60 4+60 = 64 In the second step, how did Connor come up with adding 5+5 to 50? A. He made a mistake but still happened to find the correct sum. B. He decomposed the nine from 39 into five and four, and then added the five to the five from 25. C. He knew that nine and five was 14, which can be decomposed into 5+5+4. D. None of the above.
Chapter7: Systems Of Equations And Inequalities
Section7.2: Systems Of Linear Equations: Three Variables
Problem 61SE: Last year, at Haven's Pond Car Dealership, for a particular model of BMW, Jeep, and Toyota, one...
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Connor was asked to solve the problem 39+25 twice, the first time when the problem was in a context of baseball cards, and the second time when the problem was not in a context. When Connor solved the problem the second time he described the process in these steps:
|
30+20
|
=
|
50
|
|
5+5+50
|
=
|
60
|
|
4+60
|
=
|
64
|
In the second step, how did Connor come up with adding
5+5 to 50?
He made a mistake but still happened to find the correct sum.
He decomposed the nine from 39 into five and four, and then added the five to the five from 25.
He knew that nine and five was 14, which can be decomposed into
5+5+4.
None of the above.
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