Consider a bar of n-type silicon that is uniformly doped to a value of Nd 1 x 1017 cm-3 at T= 300 K. Without an applied electric field, light is incident on %| the end of the semiconductor (shown in the figure below). Light is totally absorbed at the edge of the semiconductor (x=0), and as a result, no light enters inside the semiconductor (x>0). The light generates excess carriers at x=0: Sp(0) = &n(0) = 1 × 1015 cm-3, at steady state. Determine the steady-state excess hole and electron concentrations as a function of distance into the semiconductor. Calculate the steady-state electron and hole diffusion current densities as a function of distance into the semiconductor. Parameters: Hn=1200 cm²/V-s, µp=400 cm²/V-s, tno=10-6 s, Tpo=5×107 s. Neglect surface effects.

icon
Related questions
Question

please see attached...

Consider a bar of n-type silicon that is uniformly doped to a value of Na =
1 x 1017 cm-3 at T= 300 K. Without an applied electric field, light is incident on
the end of the semiconductor (shown in the figure below). Light is totally
absorbed at the edge of the semiconductor (x=0), and as a result, no light enters
inside the semiconductor (x>0). The light generates excess carriers at x=0:
Sp(0) = ôn(0) = 1 × 1015 cm¯3, at steady state.
Determine the steady-state excess hole and electron concentrations as a
function of distance into the semiconductor.
OCalculate the steady-state electron and hole diffusion current densities as a
function of distance into the semiconductor.
Parameters: Hn=1200 cm?/V-s, Hp=400 cm?/V-s, Tno=10° s, tpo=5×107 s. Neglect
surface effects.
Light
n-type
Transcribed Image Text:Consider a bar of n-type silicon that is uniformly doped to a value of Na = 1 x 1017 cm-3 at T= 300 K. Without an applied electric field, light is incident on the end of the semiconductor (shown in the figure below). Light is totally absorbed at the edge of the semiconductor (x=0), and as a result, no light enters inside the semiconductor (x>0). The light generates excess carriers at x=0: Sp(0) = ôn(0) = 1 × 1015 cm¯3, at steady state. Determine the steady-state excess hole and electron concentrations as a function of distance into the semiconductor. OCalculate the steady-state electron and hole diffusion current densities as a function of distance into the semiconductor. Parameters: Hn=1200 cm?/V-s, Hp=400 cm?/V-s, Tno=10° s, tpo=5×107 s. Neglect surface effects. Light n-type
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer