Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.86 × 104 N/C as shown in the figure below. 30.0 cm A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN • m?/c (b) Calculate the electric flux through the slanted surface of the box. kN • m?/c (c) Calculate the electric flux through the entire surface of the box. kN • m2/c

Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.86 × 104 N/C as shown in the figure below. 30.0 cm A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN • m?/c (b) Calculate the electric flux through the slanted surface of the box. kN • m?/c (c) Calculate the electric flux through the entire surface of the box. kN • m2/c

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

The presence of a few negative alignments of magnetic dipole moment is given by which materials? Paramagnetic Ferromagnetic Diamagnetic None of these
(b) What is the critical angle for light passing from PbO (n1= 2.67) into air (n2=1)?
Figure 2 shows a plot of electrical potential versus position along thex-axis.Make a plot of thex-component of the electric field for this situation.(imaged attached below)
A line with a uniform charge density is in the upper half of the charge xy-plane, a half of radius acreates a circle. Determine the amplitude and direction of the electric field strength at the center of the semi-circle.Determine.
What is the characteristic impedance of a single wire with a diameter d=0.25 mm placed at the center between grounded parallel planes separated by 1 mm apart? The wire is held by a material with a velocity factor of 0.75?
Electromagnetics Given A= pzsin(φ) ap. If B= curlA. Determine Bz at (p=6, φ=0.9,z=5) 4 decimals
Explain the phasor representation.
Prove that when B ,l , and are not mutually perpendicular, motional emf is given by emf=Blv sin θ.If is perpendicular to B, then θ is the angle between l and B . If l is perpendicular to B ,then θ is the angle between v and B .
Consider the figure below. (The +x axis is directed to the right.) Find the electric field (magnitude and direction) at the location of qa in the figure above, given that qb = qc = qd = 3 nC,q = −1.00 nC, and the square is 13 cm on a side.
When an ac potential of 1000 V is applied at a frequency of 1 MHz, a parallel-plate capacitor with dimensions of 38 mm by 65 mm and a plate spacing of 1.3 mm must have a minimum capacitance of 70 pF. Which of the materials listed in Table 2 might be a good fit? Why?
Explain the relationship between the direction of the electric field and the relative field strength, and equipotential lines.
At point P(-4, 3,6), if the potential field V=2x^2y – 5z, the magnitude of the electric field intensity is equal to