Consider a long bar of rectangular cross section (60 mm by 90 mm on a side) and of thermal conductivity 1 W/m-K. The surface is exposed to a convection process with air at 100°C and a convection heat transfer coefficient of 100 W/m2.K, while the remaining surfaces are maintained at 50°C. Use a grid spacing of 30 mm and the Gauss-Seidel iteration metho to solve the problem. Take an initial estimate of 0°C for all the nodal temperatures and ɛ < 0.35°C convergence criterion T, = 100°C h = 100 W/m²-K Fluid 1 - T, = 50°C Av = 30 mm T, = 50°C Ax= 30 mm T = 50°C What is the temperature of Node 2? (Note: Round off the answer up to 2 decimal places.) T2 =[ 51.45 °C

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Chapter1: Basic Modes Of Heat Transfer
Section: Chapter Questions
Problem 1.57P
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Consider a long bar of rectangular cross section (60 mm by 90 mm on a side) and of thermal conductivity 1 W/m-K. The top
surface is exposed to a convection process with air at 100°C and a convection heat transfer coefficient of 100 W/m2.K,
while the remaining surfaces are maintained at 50°C. Use a grid spacing of 30 mm and the Gauss-Seidel iteration method
to solve the problem. Take an initial estimate of 0°C for all the nodal temperatures and ɛ < 0.35°C convergence criterion.
T = 100°C
h = 100 W/m2-K
Fluid
1
T = 50°C
2
Ay = 30 mm
3
T = 50°C
Ax = 30 mm
T = 50°C
What is the temperature of Node 2?
(Note: Round off the answer up to 2 decimal places.)
T2 =
51.45 °C
Transcribed Image Text:Consider a long bar of rectangular cross section (60 mm by 90 mm on a side) and of thermal conductivity 1 W/m-K. The top surface is exposed to a convection process with air at 100°C and a convection heat transfer coefficient of 100 W/m2.K, while the remaining surfaces are maintained at 50°C. Use a grid spacing of 30 mm and the Gauss-Seidel iteration method to solve the problem. Take an initial estimate of 0°C for all the nodal temperatures and ɛ < 0.35°C convergence criterion. T = 100°C h = 100 W/m2-K Fluid 1 T = 50°C 2 Ay = 30 mm 3 T = 50°C Ax = 30 mm T = 50°C What is the temperature of Node 2? (Note: Round off the answer up to 2 decimal places.) T2 = 51.45 °C
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