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Consider a relation schema R = {A, B, C, D, E} and its functional dependency set F = {A → B,CD → E,B →D,E → A}. Which ones of the following are not candidate keys for R?
(a) A
(b) BC
(c) CD
(d) D
(e) E
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- Consider a relation schema R = {A, B, C, D, E} and its functional dependency set F = {A → B,CD → E,B →D,E → A}. Compute A+ and choose the answer.(a) A+ = AB(b) A+ = ABC(c) A+ = ABCD(d) A+= ABCDE(e) none of the aboveConsider a relation schema R = {A, B, C, D, E} and its functional dependency set F = {A → BC,CD → E,B →D,E → A}. Let R be decomposed into R1 and R2, where R1 = (A,B,C) and R2 = (A,D,E). Is the decompositionlossless? Is the decomposition dependency preserving? (a) The decomposition is lossless and dependency preserving.(b) The decomposition is neither lossless nor dependency preserving.(c) The decomposition is not lossless but dependency preserving.(d) The decomposition is lossless but not dependency preserving.Consider the universal relation: R = (A, B, C, D, E, F, G, H, I, J) and the set of functional dependencies: A, B -> C B, D -> E, F A, D -> G, H A -> I H -> J What is the key for R? And Decompose R into 2NF, and then into 3NF relations.
- Given a relation R(P ,Q ,R ,S, T, U,V,W, X,Y) and functional dependency set FD = {PQ→R,P→ST,Q→U,U→VW and S→XY} determine whether the given R is in 3NF? If not convert it into 3NF?Consider a relation schema R = {M, N, P, Q, S} and its functional dependency set F = {N → Q,S → M,M →P,P → S}. Is MN a super key of R? Is MN a candidate key of R? (a) MN is not a super key for R; MN is not a candidate key for R.(b) MN is a super key for R; MN is not a candidate key for R.(c) MN is a super key for R; MN is a candidate key for R.(d) MN is not a super key for R; MN is a candidate key for R.Consider the relation schema R(A, B, C, D, E, F) and the set S = {AB->C, BC->AD, D->E, C->B) of functional dependencies. Assuming that R is decomposed into the relation schemas R1(A,B), R2(B,C), R3(A,B,D,E) and R4(E,F). Use the Chase test to show if this is a lossless decomposition.
- Consider a relation schema R(A, B, C, D, E, G) and a set of functional dependencies F = {A → C, AD → CE, B → ACD, C → B}. (a) Show the steps of computing a canonical cover for F. (b) Compute the closure of AG and then determine whether or not AG is a candidate key. (c) Determine whether or not (A, E, G) is in BCNF and justify your answer using the transitive closure of a set of attributes. If (A, E, G) is not in BCNF, find a BCNF decomposition of it. (d) Assume that (A, E, G) is decomposed into (A, G) and (E, G). Given the above functional dependencies, is this decomposition always lossless? If so, prove this. Otherwise, explain it using an example (i.e., a case of decomposing a table containg rows and columns into two tables). (e) Assume that R is decomposed into R1(A, B, C, D) and R2(A, E, G). Is this decomposition dependency preserving? Justify your answer.Consider a relation schema R(A,B,C,D,E,H,G) F = {A->BC, B->C, C->BED, BD-> E, E->D, AG->E, G->H, AH->G} 3NF decomposition of rConsider the relation schema R (A, B, C, D) with all possible functional dependencies. For each of the following situations, identify the highest normal form for this relation R. A, C -> B, D C -> D A, C -> B, D B -> D A, C -> B, D
- Consider a relation R(A,B,C,D,E) with functional dependencies AB→C, A→D, and D→E. (a) What are the keys for R?(b)What is the closure A, that is A+ ? What is the closure AB, that is (AC)+ ?Given a relation R( P, Q, R, S, T, U, V, W, X, Y) and Functional Dependencyset FD = { PQ → R, P → ST, Q → U, U → VW, and S → XY}, determine whetherthe given R is in 3NF? If not convert it into 3 NF.Consider the schema R = (A, B, C, D, E, G) and the set F of functional dependencies:A → BCBD → ECD → AB For your decomposition, state whether it is dependency preserving and explain why ?