Consider a system of two particles in the xy-plane. For the first particle, Its mass is m₁ = 1.30 kg Its position is 7₁ = (1.202 + 2.203) m Its velocity is ₁ = (2.200€ + 0.1003) m/s For the second particle, Its mass is m₂ = 2.90 kg Its position is 72 = (-3.60% - 2.403) m Its velocity is ₂ = (2.2002 - 2.000)) m/s a. Find the position of the center of mass of the system. 7CM = ₁m+m b. Determine the velocity of the center of mass. OM = m/s + 3 m/s 2 c. What is the total linear momentum of the system? PT = kg-m/s + kg-m/s
Consider a system of two particles in the xy-plane. For the first particle, Its mass is m₁ = 1.30 kg Its position is 7₁ = (1.202 + 2.203) m Its velocity is ₁ = (2.200€ + 0.1003) m/s For the second particle, Its mass is m₂ = 2.90 kg Its position is 72 = (-3.60% - 2.403) m Its velocity is ₂ = (2.2002 - 2.000)) m/s a. Find the position of the center of mass of the system. 7CM = ₁m+m b. Determine the velocity of the center of mass. OM = m/s + 3 m/s 2 c. What is the total linear momentum of the system? PT = kg-m/s + kg-m/s
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![Consider a system of two particles in the xy-plane.
For the first particle,
Its mass is m₁ = 1.30 kg
Its position is 7¹₁ = (1.202 + 2.203) m
Its velocity is ₁ = (2.2002 + 0.100)) m/s
For the second particle,
Its mass is m₂ = 2.90 kg
Its position is 7¹2 = (-3.60% - 2.403) m
Its velocity is v₂ = (2.2001 - 2.000)) m/s
a. Find the position of the center of mass of the system.
7CM =
im+m
b. Determine the velocity of the center of mass.
UCM = 2 m/s + m/s
c. What is the total linear momentum of the system?
Pr =
kg-m/s + kg-m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d85550f-b29e-431f-b274-9520a661ac1b%2F8b04320c-c5de-4e67-8845-ba1df98419d4%2F1jrpyw_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a system of two particles in the xy-plane.
For the first particle,
Its mass is m₁ = 1.30 kg
Its position is 7¹₁ = (1.202 + 2.203) m
Its velocity is ₁ = (2.2002 + 0.100)) m/s
For the second particle,
Its mass is m₂ = 2.90 kg
Its position is 7¹2 = (-3.60% - 2.403) m
Its velocity is v₂ = (2.2001 - 2.000)) m/s
a. Find the position of the center of mass of the system.
7CM =
im+m
b. Determine the velocity of the center of mass.
UCM = 2 m/s + m/s
c. What is the total linear momentum of the system?
Pr =
kg-m/s + kg-m/s
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