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Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm. 104.5" 0.096 nm Considering the atoms as non-bonded, independent charges.... what is the net

Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm. 104.5" 0.096 nm Considering the atoms as non-bonded, independent charges.... what is the net

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Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm. 104.5" 0.096 nm T: Considering the atoms as non-bonded, independent charges... what is the net electric force vector on the oxygen atom (blue)? insidering the atoms as non-bonded, independent charges... what is the potential energy of this arrangement? Iculate the electric dipole moment (i.e. dipole vector) of the water molecule, using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two independent dipoles, and add the moments as vectors. I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative? (NOTE: The measured value of the dipole moment of water is about [p] = 0.617 x 10-29 C m, or about 1/3 of our calculated value.
Transcribed Image Text:Consider a water molecule (H₂O). The two hydrogen atoms are positively charged, the oxygen atom is doubly negatively charged. The bond angle between the hydrogen atoms is 104.5°. The oxygen-hydrogen distance is 0.096 nm. 104.5" 0.096 nm T: Considering the atoms as non-bonded, independent charges... what is the net electric force vector on the oxygen atom (blue)? insidering the atoms as non-bonded, independent charges... what is the potential energy of this arrangement? Iculate the electric dipole moment (i.e. dipole vector) of the water molecule, using the axes in the figure to establish unit vectors. Hint: Treat the molecule as two independent dipoles, and add the moments as vectors. I claim it is p = -1.88 x 10-299 Cm. Am I correct? Why is it negative? (NOTE: The measured value of the dipole moment of water is about [p] = 0.617 x 10-29 C m, or about 1/3 of our calculated value.
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