Consider an electric field E= Eo, where Eo is a constant. The flux through the shaded area (as shown in the figure) due to this field is (a) 2Ea² (c) Eça² (a,0,a) XK 1² (a,a,a) A (0,0,0) (0,a,0) (b) √2 Ea² Eoa² √√2.

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Consider an electric field E= Eo, where Eo is a constant.
The flux through the shaded area (as shown in the figure) due
to this field is
30
(a,0,a)
S DV
(a) 2E₂a²
(c) E₂a²
XK
1²
(a,a,a)
(0,0,0) (0,a,0)
→y
(b) √2Ea²
Ea²
(d)
√2
SERIK
6
Transcribed Image Text:Consider an electric field E= Eo, where Eo is a constant. The flux through the shaded area (as shown in the figure) due to this field is 30 (a,0,a) S DV (a) 2E₂a² (c) E₂a² XK 1² (a,a,a) (0,0,0) (0,a,0) →y (b) √2Ea² Ea² (d) √2 SERIK 6
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