Consider Kepler's equation regarding planetary orbits, given as M = E e sin(E), where M is the mean anomaly, E is the eccentric anomaly, and e measures eccentricity. Find the eccentric anomaly E when 7 and the eccentricity of the orbit e = 0.37. Use Newton's method with initial approximation T the mean anomaly M = Xo = 2 to find x2, rounded to the nearest thousandth. Provide your answer below: x₂ ≈
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