Consider the area between the graphs x + 5y = 15 and x + 9 = y?. This area can be computed in two different ways using integrals. One way it can be computed is as a sum of two integrals f(x). da + g(x) dr (where a < b < c) with the following values: a = b = Σ c = Σ f(x) Σ g(x) = Σ Note: Do NOT make use of absolute values when giving your answer for f(x) or g(æ) above. Alternatively, this area can be computed as a single integral | h(y) dy (where a < with the following values: a = B = Σ h(y) = Σ Note: Do NOT make use of absolute values when giving your answer for h(y) above. Either way we find that the area is Σ M M M M M

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Consider the area between the graphs x + 5y = 15 and x + 9 = y?. This area can be computed in two different ways using integrals.
One way it can be computed is as a sum of two integrals
dx +
g(x) dx
(where a < b < c)
with the following values:
a =
b =
Σ
С —
Σ
f(x) =
g(x) =
Σ
Note: Do NOT make use of absolute values when giving your answer for f(x) or g(x) above.
Alternatively, this area can be computed as a single integral
h(y) dy
(where a < B)
with the following values:
a =
Σ
h(y)
Σ
Note: Do NOT make use of absolute values when giving your answer for h(y) above.
Either way we find that the area is
Σ
M M
M M M
M M
Transcribed Image Text:Consider the area between the graphs x + 5y = 15 and x + 9 = y?. This area can be computed in two different ways using integrals. One way it can be computed is as a sum of two integrals dx + g(x) dx (where a < b < c) with the following values: a = b = Σ С — Σ f(x) = g(x) = Σ Note: Do NOT make use of absolute values when giving your answer for f(x) or g(x) above. Alternatively, this area can be computed as a single integral h(y) dy (where a < B) with the following values: a = Σ h(y) Σ Note: Do NOT make use of absolute values when giving your answer for h(y) above. Either way we find that the area is Σ M M M M M M M
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