Consider the binary search method presented in class and shown below. Suppose the method is called on an array that contains duplicate values. For example, 4 7 10 10 10 12 20 27 27 30 42. 1) public static int binarySearch(int[] a, int x) { 2) int low, high, mid; low = 0; high 5) 6) = a.length-1; while (low <= high) { mid = (low + high)/2; 10) 11) 12) 13) 14) 15) 16) if (a[mid] return mid; else if (x < a[mid]) high = mid-1; else low = mid+1; x) == } 17) 18) 19) } return -1; the method will not work correctly with duplicate values the method will work correctly, even if there are duplicate values, just as long as it is sorted O the method will work correctly, as long as no value is duplicated more than once the method will work if lines 13 and 15 are swapped none of the above

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Consider the binary search method presented in class and shown below. Suppose the
method is called on an array that contains duplicate values. For example, 4 7 10 10 10
12 20 27 27 30 42.
1) public static int binarySearch(int[] a, int x) {
int low, high, mid;
low = 0;
high =
a.length-1;
while (low <= high) {
mid = (low + high)/2;
if (a[mid]
return mid;
else if (x < a[mid])
high
10)
11)
12)
13)
14)
15)
16)
17)
18)
19) }
x)
==
= mid-1;
else
low =
mid+1;
}
return -1;
the method will not work correctly with duplicate values
O the method will work correctly, even if there are duplicate values, just as long as it is sorted
O the method will work correctly, as long as no value is duplicated more than once
O the method will work if lines 13 and 15 are swapped
none of the above
Transcribed Image Text:Consider the binary search method presented in class and shown below. Suppose the method is called on an array that contains duplicate values. For example, 4 7 10 10 10 12 20 27 27 30 42. 1) public static int binarySearch(int[] a, int x) { int low, high, mid; low = 0; high = a.length-1; while (low <= high) { mid = (low + high)/2; if (a[mid] return mid; else if (x < a[mid]) high 10) 11) 12) 13) 14) 15) 16) 17) 18) 19) } x) == = mid-1; else low = mid+1; } return -1; the method will not work correctly with duplicate values O the method will work correctly, even if there are duplicate values, just as long as it is sorted O the method will work correctly, as long as no value is duplicated more than once O the method will work if lines 13 and 15 are swapped none of the above
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