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Consider the combination of Fuel Source A and Fuel Source B: 200 kg Fuel Source A (50% S, 3% C, 12% H, 35% 0, 0% M) 350 kg Fuel Source B (0% S, 45% C, 3% H, 52% 0, 0% M) Calculate the High Calorific Power (HCP) and Low Calorific Power (LCP) in kcal given the following formula: HCP = 81C + 340 H +22S о(H-3) - 0 (H-1)- +22S 5.84(9H + M) LCP 81C + 340 H

Consider the combination of Fuel Source A and Fuel Source B: 200 kg Fuel Source A (50% S, 3% C, 12% H, 35% 0, 0% M) 350 kg Fuel Source B (0% S, 45% C, 3% H, 52% 0, 0% M) Calculate the High Calorific Power (HCP) and Low Calorific Power (LCP) in kcal given the following formula: HCP = 81C + 340 H +22S о(H-3) - 0 (H-1)- +22S 5.84(9H + M) LCP 81C + 340 H

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Consider the combination of Fuel Source A and Fuel Source B: 200 kg Fuel Source A (50% S, 3% C, 12% H, 35% 0, 0% M) 350 kg Fuel Source B (0% S, 45% C, 3% H, 52% 0, 0% M) Calculate the High Calorific Power (HCP) and Low Calorific Power (LCP) in kcal given the following formula: HCP = 81C + 340 H (H-2). +22S 8 LCP = 81C + 340 H -9). +22S 5.84(9H + M) -
Transcribed Image Text:Consider the combination of Fuel Source A and Fuel Source B: 200 kg Fuel Source A (50% S, 3% C, 12% H, 35% 0, 0% M) 350 kg Fuel Source B (0% S, 45% C, 3% H, 52% 0, 0% M) Calculate the High Calorific Power (HCP) and Low Calorific Power (LCP) in kcal given the following formula: HCP = 81C + 340 H (H-2). +22S 8 LCP = 81C + 340 H -9). +22S 5.84(9H + M) -
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