Consider the double integral XY dA Vx2 + y² I where R is the region of the XY plane, given in the attached graph. æ² + (y – 2)² = 4 r = 2+4 cos 0 R When transforming the previous integral by applying a change of variable in polar coordinates, the following is obtained r5n/6 c4 sin 0 4 sin 0 A) I = p2 sin 0 cos 0 drd0 + r sin 0 cos 0 drd0 57/6 Jo 2n/3 c4 sin 0 c4 sin 0 B) I = 01 r sin 0 cos 0 drd0 + r sin 0 cos 0 drd0 2т /3 p5n/6 c4 sin 0 r4 sin 0 C) I = r sin 0 cos 0 drd0 + r sin 0 cos 0 drd0 57/6 Jo r27/3 c4 sin 0 r4 sin 0 D) I = p2 sin 0 cos 0 drd0 + p2 sin 0 cos 0 drde

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