Consider the equation 9x2-12x +4=0, which sets a quadratic expression equal to zero. Part A Which, if any, special factoring pattern could be used in finding the factorization of the expression? A. Perfect Square Trinomial of a sum: a? +2ab + b² = (a +b)² B. Perfect Square Trinomial of a difference: a? – 2ab +b² = (a – b)² C. Difference of Squares: a2 – b² = (a +b)(a – b) D. Sum of Squares: a2 +b = (a + bi)(a – bi) - %3D %3D E. None of these Enter the Letter of your choice here (just the letter, as a capital, no periods or spaces): Part B If the expression matches one of the patterns, what are the values for the a and the b used in that pattern? (For a, enter both the coefficient and variable: for b, enter the constant: if no pattern applies (answer E, above), enter "n/a" with no quotes)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter8: Polynomials
Section8.6: Factoring Quadratic Trinomials
Problem 59PFA
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Factoring patterns
Consider the equation 9x2- 12x +4= 0, which sets a quadratic expression equal to
zero.
Part A
Which, if any, special factoring pattern could be used in finding the factorization of the
expression?
A. Perfect Square Trinomial of a sum: a? + 2ab + b² = (a +b)²
B. Perfect Square Trinomial of a difference: a? - 2ab + b? = (a – b)²
C. Difference of Squares: a2 - b = (a+ b)(a – b)
D. Sum of Squares: a2 + b = (a + bi) (a - bi)
%3D
E. None of these
Enter the Letter of your choice here (just the letter, as a capital, no periods or spaces):
Part B
If the expression matches one of the patterns, what are the values for the a and the b
used in that pattern?
(For a, enter both the coefficient and variable; for b, enter the constant; if no pattern
applies (answer E, above), enter "n/a" with no quotes)
Transcribed Image Text:Consider the equation 9x2- 12x +4= 0, which sets a quadratic expression equal to zero. Part A Which, if any, special factoring pattern could be used in finding the factorization of the expression? A. Perfect Square Trinomial of a sum: a? + 2ab + b² = (a +b)² B. Perfect Square Trinomial of a difference: a? - 2ab + b? = (a – b)² C. Difference of Squares: a2 - b = (a+ b)(a – b) D. Sum of Squares: a2 + b = (a + bi) (a - bi) %3D E. None of these Enter the Letter of your choice here (just the letter, as a capital, no periods or spaces): Part B If the expression matches one of the patterns, what are the values for the a and the b used in that pattern? (For a, enter both the coefficient and variable; for b, enter the constant; if no pattern applies (answer E, above), enter "n/a" with no quotes)
The value for a is given by the expression
The value for b is given by the constant
Part C
What is the factored form of the expression? (enter without spaces)
The factored form of the expression is given by
Type the same factored expression again:
Part D
What is the solution to the equation?
(Enter as either a single number or as two numbers separated by a comma and with no
spaces. Solutions with imaginary numbers should be entered as integeri or (fraction)i; e.g.
-2i or x = 2i would be entered as r = {-2i,2i}, while an answer of
i would be entered as a = {-(1/2)i,(1/2)i}. Note the use of
%3D
a solution of x
%3D
x = -;i or r =
parentheses, that the sign is outside of and in front of them, and that the i is outside of
and after them and that there are no spaces.)
|3D
The solution to the equation is a = {
Transcribed Image Text:The value for a is given by the expression The value for b is given by the constant Part C What is the factored form of the expression? (enter without spaces) The factored form of the expression is given by Type the same factored expression again: Part D What is the solution to the equation? (Enter as either a single number or as two numbers separated by a comma and with no spaces. Solutions with imaginary numbers should be entered as integeri or (fraction)i; e.g. -2i or x = 2i would be entered as r = {-2i,2i}, while an answer of i would be entered as a = {-(1/2)i,(1/2)i}. Note the use of %3D a solution of x %3D x = -;i or r = parentheses, that the sign is outside of and in front of them, and that the i is outside of and after them and that there are no spaces.) |3D The solution to the equation is a = {
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