Consider the figure below in which a TCP sender and receiver communicate over a connection in which the sender->receiver segments may be lost. The TCP sender sends an initial window of 5 segments. Suppose the initial value of the sender->receiver sequence number is 362 and the first 5 segments each contain 638 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t=8. As shown in the figure below, 3 of the 5 segment(s) are lost between the segment and receiver.

Consider the figure below in which a TCP sender and receiver communicate over a connection in which the sender->receiver segments may be lost. The TCP sender sends an initial window of 5 segments. Suppose the initial value of the sender->receiver sequence number is 362 and the first 5 segments each contain 638 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t=8. As shown in the figure below, 3 of the 5 segment(s) are lost between the segment and receiver.

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter8: Data And Network Communication Technology

Section: Chapter Questions

Problem 2VE

See similar textbooks

Similar questions

An audio codec generates 6 bytes of data every 20 msec. The data is transmitted by packets (every 20 msec.) using RTP over UDP over IP and finally over Ethernet. How long is each packer in bits? ____________ bits What is the header overhead in percent? _________%…
. If size of a TCP segment is 1KB and header length value is 6, the sequence number = 3500. Given that URG flag = 1 and URG pointer = 45. Then what is the total size of data. How many of them are urgent, Give the sequence numbers of urgent data.
Computer Science In Python, I am trying to make a client and server code that passes the payload with the requirements. The client has to specify the length of the data packet, up to max, specify how many times to pass the data packet, and specify the server IPv4 address. Both the client and the server need timer functions and compute the time needed to perform the number of sends both the Client and the server need to display the local and remote IPv4 addresses, total time, and bytes per second. Please help, Thanks.
(Hint: Sequence number begins from 0) An application message is divided into three TCP segments (i.e., packets), where there are 5 bytes of data in the first segment, 15 bytes in the second segment, and 20 bytes of data in the third segment. What are the sequence number of these three segments, respectively?
Subject rcs511 In an IPv4 datagram, the M bit is 0, the value of HLEN is 10, the value of total length is 400 and the fragment offset value is 300. The position of the datagram, the sequence numbers of the first and the last bytes of the payload, respectively are
TCP opens a connection using the initial sequence number (SN) 12534. The other party opens the connection with ISN 23763. The client sends 2000 bytes of data in four segments. The server then sends 2000 bytes in one segment. Use a message sequence diagram, and explain in detail the TCP based communication process.
In the packet tracer program, what settings are needed to provide the following network topology
In this case, we will use the GBN protocol with a sender window size of 4 and a sequence number range of 1,024. Assume that, at time t, the next in-order packet that the receiver is awaiting has a sequence number of k, and that the receiver is expecting it. Assume that the medium does not rearrange the messages sent to and from it. Please respond to the following questions: What are the potential sequence numbers that could be contained within the sender's window at time t?
A sender with window size (W=3) is connected to a selective repeat receiver by a link with bandwidth =106 bytes/second and propagation delay of 0.25 msec. The receiver sends Positive ACK for correctly received packets. For each packet sent, the sender sets a timer with time out value of 5 msec. On receiving an ack for a packet, the timer for that packet is cancelled. If the timer expires, that packet is retransmitted immediately. Assume that the sender sends packets 1, 2, and 3 (at t=0, packet size =1000 Bytes) and packet 2 is lost. NO other packet is lost. Under this scheme , at what time in msec would all the packets been received at the receiver.
Write a program by c programming language for VLSM calculator Input will be: 1) Input by user - IP address[sample- IP address - 192.168.1.10/24]2) Input by user - How many LAN/Networks in your topology [number of 'n'. n can be any numbers]3) Input by user - How many Host/computers in each LAN/Networks [number of 'n' in each topology. n can be any numbers] Output will be:1) Network address with subnet mask, first assignable address, last assignable address, broadcast address and gateway address for each LAN/Networks. Sample Input example for your understanding:- sample IP address - 192.168.1.10/24 ------------------------------------------ 1st LAN/Network : 258 Host/Computers2nd LAN/Network : 200 Host/Computers3rd LAN/Network : 120 Host/Computers...'n' times LAN/Network : 'n' Host/Computers Output example for your understanding:- ----------------------------------------- 1st LAN/Network : [Network address with subnet mask]1st LAN/Network : [first assignable address]1st LAN/Network :…
(a) If the second segment arrives before the first segment, in the ACK of the first arriving segment, what is the ACK number? (b) Draw and explain the 3-Way Handshake in TCP protocol.
A sender with window size (W=3) is connected to a go back N receiver by a link with bandwidth =106 bytes/second and propagation delay of 0.25 msec. The receiver sends Positive ACK for correctly received in order packets. For each packet sent, the sender sets a timer with time out value of 5 msec. On receiving an ack for that packet, the timer is cancelled. If the timer expires, that packet is retransmitted immediately. Assume that the sender sends packets 1, 2, and 3 (at t=0, packet size =1000 Bytes) and packet 2 is lost. NO other packet is lost. Under this scheme , at what time (in msec) would all the packets been received at the receiver.