Consider the following equation. cos x= x (a) Prove that the equation has at least one real root. Pv0 7 -0.46, there is a number f(x) = cos x - x is continuous on theinterval [0, 1], (0) = c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x - x- ?0, and f(1) - cos 1-1- -0.46 ?0. Since or cos xx, in the interval (0, 1). (b) Use your calculator to find an interval of length 0.01 that contains a root. (Enter your answer using interval notation.)

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter5: Rings, Integral Domains, And Fields
Section5.4: Ordered Integral Domains
Problem 5E: 5. Prove that the equation has no solution in an ordered integral domain.
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Using interval notation for B please 

Consider the following equation.
cos x = x3
(a) Prove that the equation has at least one real root.
? 0?v -0.46, there is a number
f(x) = cos x –- x³ is continuous on theinterval [0, 1], f(0) =
c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x - x =
? v0, and f(1) = cos 1 - 1 = -0.46 ? v 0. Since
%3D
or cos x = x, in the interval (0, 1).
%3D
%3D
(b) Use your calculator to find an interval of length 0.01 that contains a root. (Enter your answer using interval notation.)
Transcribed Image Text:Consider the following equation. cos x = x3 (a) Prove that the equation has at least one real root. ? 0?v -0.46, there is a number f(x) = cos x –- x³ is continuous on theinterval [0, 1], f(0) = c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x - x = ? v0, and f(1) = cos 1 - 1 = -0.46 ? v 0. Since %3D or cos x = x, in the interval (0, 1). %3D %3D (b) Use your calculator to find an interval of length 0.01 that contains a root. (Enter your answer using interval notation.)
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