Consider the following equation. Fox, y) = sin(4x + 4y), P(-8, 8), u=V3i -i) (a) Find the gradient of f. Dx, V) = (b) Evaluate the gradient at the point P. D(-8, 8) = (C) Find the rate of change of fat Pin the direction of the vector u. DA-8, 8) =
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- Find the gradient of the function g(x,y) = xy at the point (4, - 4). Then sketch the gradient together with the level curve that passes through the point. First find the gradient vector at (4, - 4). Vg(4, - 4) =i (Di (Simplify your answers.) li +Find the maximum rate of change of f at the given point and the direction in which it occurs. f(x, y) =8xy2, (5,-7) maximum rate of change direction vectorI would need help with a, b, and c as mention below. (a) Find the gradient of f.(b) Evaluate the gradient at the point P.(c) Find the rate of change of f at P in the direction of the vector u.
- Find the gradient of the function g(x,y) = xy at the point (5, 4). Then sketch the gradient together with the level curve that passes through the point. First find the gradient vector at (5, -4). Vg(5,-4)=i+ (Simplify your answers.)× Find the maximum rate of change of f at the given point and the direction in which it occurs. f(x, y) = y²/x, (2, 4) direction of maximum rate of change (in unit vector) = < maximum rate of change =Find the gradient of the function g(x,y) = xy2 at the point (4, - 4). Then sketch the gradient together with the level curve that passes through the point. First find the gradient vector at (4, - 4). Vg(4, - 4) = i + ( Di (Simplify your answers.) Choose the graph that shows the level curve and the gradient vector at (4, - 4). OA. O B. Oc. D. Ay
- Find the gradient of the function g(x,y) = xy2 at the point (4, - 1). Then sketch the gradient together with the level curve that passes through the point. ..... First find the gradient vector at (4, - 1). Vg(4, - 1) = i+ ( Di (Simplify your answers.) Choose the graph that shows the level curve and the gradient vector at (4, - 1). O A. OB. OC. OD. AY AY AY QFind the gradient of w= 3x² - 5y + 22 at the point (1, 1, -2)The directional derivative of the functionf (x, y) = -y³ at the point (-3, –2) in the direction of the vector i = (-4, –3).
- Consider the following equation (151) f(x, у) - у/x, P(1, 3), 2i (a) Find the gradient of f. Vf(x, y) (b) Evaluate the gradient at the point P. Vf(1, 3) = (c) Find the rate of change of f at P in the direction of the vector u. Duf(1, 3)Use the gradient to find the directional derivative of the function at P in the direction of Q. f(x, y) = 3x2 - y² + 4, P(7,7), Q(8, 4)Find the directional derivative of the function at the given point in the direction of vector v. f(x, y) = 2 + 6x√y, (4, 16), v = (4, -3) Duf(4,16) =