Consider the following line of code: X = new int*[n]; What should the type of x be? O int O int* O int** O int& O None of the above
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![Consider the following line of code:
X = new int*[n];
What should the type of x be?
O int
O int*
O int**
O int&
O None of the above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf89c864-71e5-4449-bde3-4774682a1969%2Fcf3d5947-8640-49c3-a13d-3f9dc524f4f8%2Fn37zbb_processed.png&w=3840&q=75)
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- What will be the value of x[8] after the following code is executed? final int NUM = 10;int[] x = new int[NUM];int y = 1;for (int i = 0; i < NUM; i++){x[i] = y;y++;} 1 9 7 5Assume that int a[ 2 ][ 2 ] = { { 1, 2 }, { 3, 4 } }; the value of a[ 1, 1 ] = ______;int i = 10; int j = 4; int k = i / j; int l = j % i; What is k and l?
- What is the value of x after the following code executes? double m = 2.67;int x = (int)m;1 int[] a = new int[n]; 2 a[0] = 0; a[1] = 1; 3 int x = 0; 4 for (int i = 2; i < n; i++) { 5 x = 3 * (i-1) * (i-1); 6 x += 3 * i - 2; 7 a[i] = a[i-1] + x; 8 } The code can be simplified by replacing lines 5, 6, 7 with a single line of code. Write the single line of code below:1) #include #include int power(int, int); int main(void) { int x, n; printf("Enter a number and powerto raise it to: "); scanf_s("%d %d", &x, &n); printf("Result: %d\n", power(n, x)); return 0; } int power(int x, int n) { int m; if (n == 0) return 1; if (n % 2 == 0) { m = power(x, n / 2); return m * m; } else return x * power(x, n - 1); } 2) #include int hcf(int n1, int n2); int main() { int n1, n2; printf("Enter any two positive integers: "); scanf("%d %d", &n1, &n2); printf("Greatest Common Divisor of %d and %d is %d.", n1, n2, hcf(n1,n2)); return 0; } int hcf(int n1, int n2) { if (n2 != 0) return hcf(n2, n1%n2); else return n1; } 3) #include int main() { int array[], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) {…
- (b) This code has a problem. What is it? How is it called? double x = 1.5, y = 3.4; double* p = &x; double* p2 = new double[12]; *p += y; p = &y; *p *= 2; for (int i{ 0 }; i < 12; ++i) { p2[i] = 1.6; } p2 = p; delete p2;Trace the following code and give the output int a = 6, b = 8; int c = (a < b) ? a : b; int v = c; while (v%a != 0 || v%b != 0) v += c; cout << v;int const MULTIPLIER = 5; is a valid way to declare a constant integer variable. Group of answer choices True False ------- Given the following code segment, what is output to the screen? int num1 = 6; int num2 = 4 * num1++; cout << "num1=" << num1 << " num2=" << num2; Group of answer choices num1=7 num2=24 num1=6 num2=24 num1=6 num2=28 Nothing, because the code does not compile.
- Identify all private, shared variables in the following code snippet. What is the output of the program (e.g. the value of IS)? int A[100]; int count; void work(int index[]) { float B[10]; …… } void main(){ int IS = 10; int i=0; #pragma omp parallel private(i) { int index[10]; work(index); #pragma omp for reduction(+:IS) for(i=0;i<100;i++) { IS = IS + i; } } printf(“%i\n”, IS); }Consider the following statement:int* p, q;This statement could lead to what type of misinterpretation?What is the the output of the following code? int **p;p = new int* [5];for (int i = 0; i < 5; i++)p[i] = new int[3];for (int i = 1; i < 5; i++) for (int j = 0; j < 3; j++)p[i][j] = 2 * i + j;for (int i = 1; i < 5; i++){for (int j = 0; j < 3; j++)cout << p[i][j] << " ";cout << endl;}