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Consider the following reaction: 4PC13(g) - Pa(g) + 6C12(g) If the initial concentration of PC13(g) is 1.0 mol/L, and "x" is the equilibrium concentration of Cl2(g), what is the correct equilibrium relation O a. Kc=x7/6 b. Kc=((x/6)*x)/(1.0-2x/3)4 O c. Kc=x'/(1.0-2x/3)ª O d. Kc=((x/6)*x)/(1.0-2x/3)4 e. Kc=((x/6)*x)/(1.0-2x/3)

Consider the following reaction: 4PC13(g) - Pa(g) + 6C12(g) If the initial concentration of PC13(g) is 1.0 mol/L, and "x" is the equilibrium concentration of Cl2(g), what is the correct equilibrium relation O a. Kc=x7/6 b. Kc=((x/6)*x)/(1.0-2x/3)4 O c. Kc=x'/(1.0-2x/3)ª O d. Kc=((x/6)*x)/(1.0-2x/3)4 e. Kc=((x/6)*x)/(1.0-2x/3)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Consider the following reaction: 4PC13(g) → PA(g) + 6C12(g) If the initial concentration of PC13(g) is 1.0 mol/L, and "x" is the equilibrium concentration of Cl2(g), what is the correct equilibrium relation O a. Kc=x7/6 O b. Kc=((x/6)*x)/(1.0-2x/3)4 O c. Kc=x/(1.0-2x/3)4 O d. Kc=(x/6)*x)/(1.0-2x/3)4 O e. Kc=(x/6)*x)/(1.0-2x/3)
Transcribed Image Text:Consider the following reaction: 4PC13(g) → PA(g) + 6C12(g) If the initial concentration of PC13(g) is 1.0 mol/L, and "x" is the equilibrium concentration of Cl2(g), what is the correct equilibrium relation O a. Kc=x7/6 O b. Kc=((x/6)*x)/(1.0-2x/3)4 O c. Kc=x/(1.0-2x/3)4 O d. Kc=(x/6)*x)/(1.0-2x/3)4 O e. Kc=(x/6)*x)/(1.0-2x/3)
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