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Consider the following statement. For all positive real numbers r and s, Vr+s # Vr + Vs. Construct a proof by contradiction for the statement by selecting sentences from the following scrambled list and putting them in the correct order. By the zero product property, at least one of vr or Vs equals 0, which implies that r or s equals 0. But this is a contradiction because r and s are positive. Simplifying the equation gives that 0 2rs. Simplifying the equation gives that 0 = 2yrys. Squaring both sides of the equation gives that r +s = r + 2yrys + s. By the zero product property, at least one of r or s equals 0. Squaring both sides of the equation gives that r + s =r + 2rs + s. Proof by contradiction: 1. Suppose not. That is, suppose there exists positive real numbers r and s such that Vr + s = Vr + vs. 2. By the zero product property, at least one of v(r) or V(s) equals 0, which implies that r or s equals 0. v Select-- 3. 4. Select--- 5. Select- 6. Thus, we have reached a contradiction and have proved the statement.

Consider the following statement. For all positive real numbers r and s, Vr+s # Vr + Vs. Construct a proof by contradiction for the statement by selecting sentences from the following scrambled list and putting them in the correct order. By the zero product property, at least one of vr or Vs equals 0, which implies that r or s equals 0. But this is a contradiction because r and s are positive. Simplifying the equation gives that 0 2rs. Simplifying the equation gives that 0 = 2yrys. Squaring both sides of the equation gives that r +s = r + 2yrys + s. By the zero product property, at least one of r or s equals 0. Squaring both sides of the equation gives that r + s =r + 2rs + s. Proof by contradiction: 1. Suppose not. That is, suppose there exists positive real numbers r and s such that Vr + s = Vr + vs. 2. By the zero product property, at least one of v(r) or V(s) equals 0, which implies that r or s equals 0. v Select-- 3. 4. Select--- 5. Select- 6. Thus, we have reached a contradiction and have proved the statement.

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter10: Inequalities
Section10.2: Solving Inequalities
Problem 62WE
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Consider the following statement. For all positive real numbers r and s, Vr + s # Vr + Vs. Construct a proof by contradiction for the statement by selecting sentences from the following scrambled list and putting them in the correct order. By the zero product property, at least one of vr or Vs equals 0, which implies that r or s equals 0. But this is a contradiction because r and s are positive. Simplifying the equation gives that 0 2rs. Simplifying the equation gives that 0 = 2yrys. Squaring both sides of the equation gives that r + s = r + 2VTVS+ s. By the zero product property, at least one of r or s equals 0. Squaring both sides of the equation gives that r + s =r + 2rs + s. Proof by contradiction: 1. Suppose not. That is, suppose there exists positive real numbers r and s such that Vr + s = Vr + vs. 2. By the zero product property, at least one of v(r) or V(s) equals 0, which implies that r or s equals 0. v Select-- 3. 4. Select--- 5. Select- 6. Thus, we have reached a contradiction and have proved the statement.
Transcribed Image Text:Consider the following statement. For all positive real numbers r and s, Vr + s # Vr + Vs. Construct a proof by contradiction for the statement by selecting sentences from the following scrambled list and putting them in the correct order. By the zero product property, at least one of vr or Vs equals 0, which implies that r or s equals 0. But this is a contradiction because r and s are positive. Simplifying the equation gives that 0 2rs. Simplifying the equation gives that 0 = 2yrys. Squaring both sides of the equation gives that r + s = r + 2VTVS+ s. By the zero product property, at least one of r or s equals 0. Squaring both sides of the equation gives that r + s =r + 2rs + s. Proof by contradiction: 1. Suppose not. That is, suppose there exists positive real numbers r and s such that Vr + s = Vr + vs. 2. By the zero product property, at least one of v(r) or V(s) equals 0, which implies that r or s equals 0. v Select-- 3. 4. Select--- 5. Select- 6. Thus, we have reached a contradiction and have proved the statement.
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