Consider the following surface. the part of the plane 2x + 5y + z = 10 that lies in the first octant Find the area of the region D in the xy-plane that lies below the surface. A(D) = Find the area of the surface. 2 = 1/₂ ( √₁₂ ² + 1₁² ) dA = A(S) = 2π 3 [26√/26 -1]

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