Consider the following vector function. r(t): (6√2t, e6t, e-6t) (a) Find the unit tangent and unit normal vectors T(t) and N(t). 6e -6t) (6√2, 6e6t, - be √72+36e¹2t+36e -12t T(t) N(t) = = k(t) (b) Use this formula to find the curvature. √2 = 2+e¹2t X te -12t

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