Consider the following. 8x² + y² = 5x (a) Find y' by implicit differentiation. - y' = 5-32x 71,6 3 (b) Solve the equation explicitly for y and differentiate to get y' in terms of x. 5-321³ 75x8) y' = 6 X (c) Check that your solutions to parts (a) and (b) are consistent by substituting the expression for y into your solution for part (a).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the following.
esc
K
8x² + y² = 5x
(a) Find y' by implicit differentiation.
→1
y' =
5-32x³
7y6
(b) Solve the equation explicitly for y and differentiate to get y' in terms of x.
5-32x³
75x – 8,3)
-
y' =
y' =
(c) Check that your solutions to parts (a) and (b) are consistent by substituting the expression for y into your solution for part (a).
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Transcribed Image Text:Consider the following. esc K 8x² + y² = 5x (a) Find y' by implicit differentiation. →1 y' = 5-32x³ 7y6 (b) Solve the equation explicitly for y and differentiate to get y' in terms of x. 5-32x³ 75x – 8,3) - y' = y' = (c) Check that your solutions to parts (a) and (b) are consistent by substituting the expression for y into your solution for part (a). Type here to search fi ? A f2 2 X S f3 # 3 W E D f4 $ OG a IOI 4 f5 % 5 F f6 R T O 6 31 f7 & Y 7 G H f8 + U 8 J fg KAA (
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