Consider the following. x tan2(e), y sec(0),-n/2 < < n/2 (a) Eliminate the parameter to find a Cartesian equation of the curve X (b) Sketch the curve and indicate with an arrow the direction in which the curve is traced as the parameter increases у у 3.0 3.0 2.5 2.5 2.0 2.0 1.5 1.5 1.0 1.0 0.5 0.5 х 0.5 1.0 1.5 2.0 2.5 3.0 0.5 1.0 1,5 2,0 2.5 3.0 O у у 3.0 3,0 2.5 2.5 2.0 2.0 1.5 1.5 1.0 1.0 0.5 0.5 X 0.5 1.0 1.5 2.0 2.5 3.0 0.5 1.0 1.5 2.0 2.5 3.0

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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I thought that since (tan x)^2 + 1 = (sec x)^2, I could use that 1 = (sec x)^2 - (tan x)^2. But I did not get the correct answer. Am I using the wrong approach?

Consider the following.
x tan2(e),
y sec(0),-n/2 < < n/2
(a) Eliminate the parameter to find a Cartesian equation of the curve
X
(b) Sketch the curve and indicate with an arrow the direction in which the curve is traced as the parameter increases
у
у
3.0
3.0
2.5
2.5
2.0
2.0
1.5
1.5
1.0
1.0
0.5
0.5
х
0.5
1.0
1.5
2.0
2.5
3.0
0.5
1.0
1,5
2,0
2.5
3.0
O
у
у
3.0
3,0
2.5
2.5
2.0
2.0
1.5
1.5
1.0
1.0
0.5
0.5
X
0.5
1.0
1.5
2.0
2.5
3.0
0.5
1.0
1.5
2.0
2.5
3.0
Transcribed Image Text:Consider the following. x tan2(e), y sec(0),-n/2 < < n/2 (a) Eliminate the parameter to find a Cartesian equation of the curve X (b) Sketch the curve and indicate with an arrow the direction in which the curve is traced as the parameter increases у у 3.0 3.0 2.5 2.5 2.0 2.0 1.5 1.5 1.0 1.0 0.5 0.5 х 0.5 1.0 1.5 2.0 2.5 3.0 0.5 1.0 1,5 2,0 2.5 3.0 O у у 3.0 3,0 2.5 2.5 2.0 2.0 1.5 1.5 1.0 1.0 0.5 0.5 X 0.5 1.0 1.5 2.0 2.5 3.0 0.5 1.0 1.5 2.0 2.5 3.0
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