Consider the following. y 6F y = x' - 2 x 4 X -4 -2 2 y = 2 x - 4 (a) Find the points of intersection of the curves. (х, у) 3D (smallest x-value) (х, у) %3D (х, у) %3 (largest y-value) (b) Form the integral that represents the area of the shaded region. 2 dx + dx (c) Find the area of the shaded region.
Consider the following. y 6F y = x' - 2 x 4 X -4 -2 2 y = 2 x - 4 (a) Find the points of intersection of the curves. (х, у) 3D (smallest x-value) (х, у) %3D (х, у) %3 (largest y-value) (b) Form the integral that represents the area of the shaded region. 2 dx + dx (c) Find the area of the shaded region.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the following.
The x y-coordinate plane is given. A line y = 2x, a curve y = x3 − 2x, and a shaded region are graphed.
- The line enters the window in the third quadrant, goes up and right, passes through the point (−2, −4) crossing the curve, crosses the x-axis at the origin crossing the curve, passes through the point (2, 4) crossing the curve, and exits the window in the first quadrant.
- The curve enters the window in the third quadrant, goes up and right becoming less steep, passes through the point (−2, −4) crossing the line, crosses the x-axis at approximately x = −1.41, changes direction at the approximate point (−0.82, 1.1), goes down and right becoming more steep, passes through the origin crossing the line, goes down and right becoming less steep, changes direction at the approximate point (0.82, −1.1),goes up and right becoming more steep, crosses the x-axis at approximately x = 1.41, passes through the point (2, 4) crossing the line, and exits the window in the first quadrant.
- The area between the line and the curve is shaded from x = −2 to x = 2.
(a) Find the points of intersection of the curves.
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