Consider the following. y = x4 -8x³ + 16x² Find the relative maxima, relative minima, and points of inflection. (If an answer does not exist, enter DNE.) x 0 relative maxima relative minima relative minima points of inflection points of inflection >>=((2,16) (x, y) = (x, y) = -((0,0) (x, y) = (x, y) x (smaller x-value) (4,0) x ! 6-2√3 64 3 9 6+2√3 64 I 3 (larger x-value) x(smaller x-value) x (larger x-value)
Consider the following. y = x4 -8x³ + 16x² Find the relative maxima, relative minima, and points of inflection. (If an answer does not exist, enter DNE.) x 0 relative maxima relative minima relative minima points of inflection points of inflection >>=((2,16) (x, y) = (x, y) = -((0,0) (x, y) = (x, y) x (smaller x-value) (4,0) x ! 6-2√3 64 3 9 6+2√3 64 I 3 (larger x-value) x(smaller x-value) x (larger x-value)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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