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Consider the function g : (6, 0) → R given by, 3x g(x) : x-6 Then we have that lim g(x) =3 . %3D x→∞ Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then Ig(x) – 3| < e. The smallest value for M in terms of e is М — Note: • Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077. • the Maple syntax for |æ| is abs (x), and the syntax for e is epsilon.

Consider the function g : (6, 0) → R given by, 3x g(x) : x-6 Then we have that lim g(x) =3 . %3D x→∞ Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then Ig(x) – 3| < e. The smallest value for M in terms of e is М — Note: • Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077. • the Maple syntax for |æ| is abs (x), and the syntax for e is epsilon.

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section: Chapter Questions
Problem 11T: Consider the following rational functions: r(x)=x2x22x1 s(x)=x2+4x3+27 t(x)=x+2x39x u(x)=x225x2+x6...
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Consider the function g : (6, 00) → R given by, 3x g(x) = x-6 Then we have that lim g(x) = 3. Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then |g(x) – 3| < e. The smallest value for M in terms of e is M = Note: Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077. the Maple syntax for x is abs (x), and the syntax for e is epsilon.
Transcribed Image Text:Consider the function g : (6, 00) → R given by, 3x g(x) = x-6 Then we have that lim g(x) = 3. Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then |g(x) – 3| < e. The smallest value for M in terms of e is M = Note: Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077. the Maple syntax for x is abs (x), and the syntax for e is epsilon.
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