Consider the functional S[y] = =ffdx [₁ = dx ln(1 + x²y'), y(1) = 0, y(2) = A, where A is a constant and y is a continuously differentiable function for 1 ≤ x ≤ 2. Let h be a continuously differentiable function for 1 ≤ x ≤ 2, and let e be a constant. Let A = S[y+ ch] - S[y]. (a) Show that x²h' 24h2 A = c ² da 4²² - ² ² dx + 22/7² +0(8³). dx 1 1 + x²y' 2 (1+x²y')²
Consider the functional S[y] = =ffdx [₁ = dx ln(1 + x²y'), y(1) = 0, y(2) = A, where A is a constant and y is a continuously differentiable function for 1 ≤ x ≤ 2. Let h be a continuously differentiable function for 1 ≤ x ≤ 2, and let e be a constant. Let A = S[y+ ch] - S[y]. (a) Show that x²h' 24h2 A = c ² da 4²² - ² ² dx + 22/7² +0(8³). dx 1 1 + x²y' 2 (1+x²y')²
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.2: Partial Derivatives
Problem 48E
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![Consider the functional
S[y] = f²
- [² de In
dæ In(1+x²y'), y(1) = 0, y(2) = A,
where A is a constant and y is a continuously differentiable function for
1 ≤ x ≤ 2. Let h be a continuously differentiable function for 1 ≤ x ≤ 2,
and let e be a constant. Let A = S[y+ ch] - S[y].
€
(a) Show that
= €
ef da - 2
+2 x²h'
1 + x²y'
dx
S
dx
24h2
(1 + x² y')²
+0(€³).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F59d44c96-efb1-4f3c-83b3-5a6a84cf94cb%2Fad4c5777-a657-4657-b658-60b9c14ebe14%2Fyzm9ku_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the functional
S[y] = f²
- [² de In
dæ In(1+x²y'), y(1) = 0, y(2) = A,
where A is a constant and y is a continuously differentiable function for
1 ≤ x ≤ 2. Let h be a continuously differentiable function for 1 ≤ x ≤ 2,
and let e be a constant. Let A = S[y+ ch] - S[y].
€
(a) Show that
= €
ef da - 2
+2 x²h'
1 + x²y'
dx
S
dx
24h2
(1 + x² y')²
+0(€³).
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