Consider the graphs, shown below, of the functions f(x) (blue, first graph) and g(x) (red, second graph). For which values of a E (-3,3) does lim(f(x) – g(x) not exist? -2 -1 2 3 -3 -2 1 1 -3- O a = -3, a = -2, a = 2 and a = 3 O a = 2 a = -2, a = 2 and a = 3 O a = -2 and a = 2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.4: Logarithmic Functions
Problem 44E
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Consider the graphs, shown below, of the functions f(x) (blue, first graph) and g(x) (red, second graph). For
which values of a E (-3,3) does lim(f(x) – g(x) not exist?
2
-2
-1
1
2
3
3
-2
1
1
-3-
O a = -3, a = -2, a = 2 and a = 3
O a = 2
a =
-2, a = 2 and a = 3
O a = -2 and a = 2
Transcribed Image Text:Consider the graphs, shown below, of the functions f(x) (blue, first graph) and g(x) (red, second graph). For which values of a E (-3,3) does lim(f(x) – g(x) not exist? 2 -2 -1 1 2 3 3 -2 1 1 -3- O a = -3, a = -2, a = 2 and a = 3 O a = 2 a = -2, a = 2 and a = 3 O a = -2 and a = 2
The Squeeze Law states: Suppose that g(x) < f(x) < h(x) for all æ near a, and that
lim g(x)
lim h(x) = L.
xa
Then lim f(x) exists and is equal to L.
Consider the limit
a sine)
lim x° sin
What is a suitable choice for g(x) and h(x) to show that lim x° sin
= 0?
g(x) = -|æ|° and h(x) = |æ|°
O g(x) = | – x|° and h(x) = |¤|°
g(æ) = -| sin | and h(x) = | sin |
g(x) = -x³ and h(x) = x³
Transcribed Image Text:The Squeeze Law states: Suppose that g(x) < f(x) < h(x) for all æ near a, and that lim g(x) lim h(x) = L. xa Then lim f(x) exists and is equal to L. Consider the limit a sine) lim x° sin What is a suitable choice for g(x) and h(x) to show that lim x° sin = 0? g(x) = -|æ|° and h(x) = |æ|° O g(x) = | – x|° and h(x) = |¤|° g(æ) = -| sin | and h(x) = | sin | g(x) = -x³ and h(x) = x³
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